0基础第20讲课后题，感觉答案不对吧？

fang232629

这是题目：
1. 请用已学过的知识编写程序，找出小甲鱼藏在下边这个长字符串中的密码，密码的埋藏点符合以下规律：
    a) 每位密码为单个小写字母Powered by bbs.fishc.com
    b) 每位密码的左右两边均有且只有三个大写字母
然后这是标准答案：

1. str1 = '''ABSaDKSbRIHcRHGcdDIF'''     #str1的字符串内容在下面，替换一下就好
   
2. 
   
3. countA = 0  # 统计前边的大写字母
   
4. countB = 0  # 统计小写字母
   
5. countC = 0  # 统计后边的大写字母
   
6. length = len(str1)
   
7. 
   
8. for i in range(length):
   
9.     if str1[i] == '\n':
   
10.         continue
    
11. 
    
12.     """
    
13.     |如果str1[i]是大写字母：
    
14.     |-- 如果已经出现小写字母：
    
15.     |-- -- 统计后边的大写字母
    
16.     |-- 如果未出现小写字母：
    
17.     |-- -- 清空后边大写字母的统计
    
18.     |-- -- 统计前边的大写字母
    
19.     """
    
20.     if str1[i].isupper():
    
21.         if countB:
    
22.             countC += 1
    
23.         else:
    
24.             countC = 0
    
25.             countA += 1
    
26. 
    
27.     """
    
28.     |如果str1[i]是小写字母：
    
29.     |-- 如果小写字母前边不是三个大写字母（不符合条件）：
    
30.     |-- -- 清空所有记录，重新统计
    
31.     |-- 如果小写字母前边是三个大写字母（符合条件）：
    
32.     |-- -- 如果已经存在小写字母：
    
33.     |-- -- -- 清空所有记录，重新统计（出现两个小写字母）
    
34.     |-- -- 如果该小写字母是唯一的：
    
35.     |-- -- -- countB记录出现小写字母，准备开始统计countC
    
36.     """
    
37.     if str1[i].islower():
    
38.         if countA != 3:
    
39.             countA = 0
    
40.             countB = 0
    
41.             countC = 0
    
42.         else:
    
43.             if countB:
    
44.                 countA = 0
    
45.                 countB = 0
    
46.                 countC = 0
    
47.             else:
    
48.                 countB = 1
    
49.                 countC = 0
    
50.                 target = i
    
51. 
    
52.     """
    
53.     |如果前边和后边都是三个大写字母：
    
54.     |-- 如果后边第四个字母也是大写字母（不符合条件）：
    
55.     |-- -- 清空记录B和C，重新统计
    
56.     |-- 如果后边仅有三个大写字母（符合所有条件）：
    
57.     |-- -- 打印结果，并清空所有记录，进入下一轮统计
    
58.     """
    
59.     if countA == 3 and countC == 3:
    
60.         if i+1 != length and str1[i+1].isupper():
    
61.             countB = 0
    
62.             countC = 0
    
63.         else:
    
64.             print(str1[target], end='')
    
65.             countA = 3
    
66.             countB = 0
    
67.             countC = 0
    

复制代码

然后这是我的解题：

str1 = '''ABSaDKSbRIHcRHGcdDIF'''   #str1的字符串内容在下面，替换一下就好pwd = []
count = 3
for each in str1[3:-4]:

    if each.islower():
        if not (str1[count-3].islower() and str1[count-2].islower() and str1[count-1].islower() and str1[count+1].islower() and str1[count+2].islower() and str1[count+3].islower()):
            pwd.append(each)
        else:
            continue
    else:
        continue
    count += 1

for i in pwd:
    print(i, end='')

str1是下面的内容

ACFlCTLIQlAIVMTqHFkswqbDDHtpgcWaXSSglUYKE
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qKWGc

我的运行结果：

llqkswqbtpgcagllqsyazrbkrgtlqhpwquqpslfllwptqjruzwvbxoritpgadkzvnvmlsmqydqyboenkuiiikspgsmhnppfmkpjjceavgsvkgtzleephrpxqinuwursznpxhstpdzqenttlibhbpwsthiwzambmqmwofyxmczjcffccbzhudsaspjrvanrqanmbobftkjjhleauuiaqisgm

我感觉挺符合题目要求的啊。难道我理解错了？