[已解决]列表和元组的转换

九御寒

lst = [("triangle", "shape"), ("red", "color"), ("square", "shape"), ("yellow", "color"), ("green", "color"),
       ("circle", "shape")]
lst_new = [[x[1], x[0]] for x in lst]
# print(lst_new)
lst_sort = sorted(lst_new)
print(f"按照标签排序后的列表：{lst_sort}")
lst_colors = [x[1] for x in lst_sort if x[0] == "color"]
print(f"颜色列表：{lst_colors}")


结果：
按照标签排序后的列表：[['color', 'green'], ['color', 'red'], ['color', 'yellow'], ['shape', 'circle'], ['shape', 'square'], ['shape', 'triangle']]
颜色列表：['green', 'red', 'yellow']

怎么样才可以让['color', 'green']的[]变成（）

最佳答案

月排行榜 / 总排行榜

isdkz

2022-3-15 19:15:26

lst_new = [(x[1], x[0]) for x in lst]       # 这个由中括号改成小括号

跳转到最佳答案楼层

ckblt

lst_colors = tuple(lst_colors)

isdkz

lst = [("triangle", "shape"), ("red", "color"), ("square", "shape"), ("yellow", "color"), ("green", "color"),
       ("circle", "shape")]
lst_new = [(x[1], x[0]) for x in lst]
# print(lst_new)
lst_sort = sorted(lst_new)
print(f"按照标签排序后的列表：{lst_sort}")
lst_colors = [x[1] for x in lst_sort if x[0] == "color"]
print(f"颜色列表：{lst_colors}")

isdkz

lst_new = [(x[1], x[0]) for x in lst]       # 这个由中括号改成小括号