[已解决]请教各位老师

redaiconglin

我的代码是这样
a =['b','c']
b = [1,2,3,4,56]

j = []
def s():
    for i in a:
        for each in b:
          j.append(str(each)+i)
    return j
if __name__=='__main__':
    d = [1, 2, 3]
    h =[]
    for g in d:
        h.extend(s())
    print(h)
能达到的效果是这样
['1b', '2b', '3b', '4b', '56b', '1c', '2c', '3c', '4c', '56c', '1b', '2b', '3b', '4b', '56b', '1c', '2c', '3c', '4c', '56c', '1b', '2b', '3b', '4b', '56b', '1c', '2c', '3c', '4c', '56c']
如何做才能达到这样的效果
['1b', '2b', '3b', '4b', '56b', '1b', '2b', '3b', '4b', '56b', '1b', '2b', '3b', '4b', '56b', '1c', '2c', '3c', '4c', '56c', '1c', '2c', '3c', '4c', '56c', '1c', '2c', '3c', '4c', '56c']
请各位老师帮帮我谢谢了

最佳答案

月排行榜 / 总排行榜

isdkz

2022-4-27 17:57:34

1. a =['b','c']
   
2. b = [1,2,3,4,56]
   
3. 
   
4. j = []
   
5. def s(count=1):
   
6.     for i in a:
   
7.         for each in count * b:
   
8.           j.append(str(each)+i)
   
9.     return j
   
10. if __name__=='__main__':
    
11.     h = s(3)
    
12.     print(h)

复制代码

跳转到最佳答案楼层

jackz007

1. def s(j , c , b):
   
2.     for _ in range(2):
   
3.         for each in b:
   
4.             j . append(str(each) + c)
   
5. 
   
6. if __name__=='__main__':
   
7.     a , b , h = ['b','c'] , [1,2,3,4,56] , []
   
8.     for x in a:
   
9.         s(h , x , b)
   
10.     print(h)

复制代码

isdkz

1. a =['b','c']
   
2. b = [1,2,3,4,56]
   
3. 
   
4. j = []
   
5. def s(count=1):
   
6.     for i in a:
   
7.         for each in count * b:
   
8.           j.append(str(each)+i)
   
9.     return j
   
10. if __name__=='__main__':
    
11.     h = s(3)
    
12.     print(h)

复制代码

isdkz

1. a, b, s = ['b','c'], [1,2,3,4,56], lambda count=1:[str(each)+i for i in a for each in count * b]
   
2. print(s(3))

复制代码

redaiconglin

isdkz 发表于 2022-4-27 18:05

感谢老师的讲解。谢谢

redaiconglin

jackz007 发表于 2022-4-27 17:56

感谢老师的讲解谢谢了