[已解决]获取字典的两个值，并以字符串形式添加到列表里

如明境

glds = [{"a":1,"b":2,"c":3}{"a":4,"b":5,"c":6}{"a":7,"b":8,"c":9}]
gid = []
    for gld in glds:
        gid.extend(str(gld['a'],gld['b']))
    print(gid)

运行时提示TypeError: str() argument 2 must be str, not int  有没有什么办法解决这个问题

最佳答案

月排行榜 / 总排行榜

isdkz

2022-5-10 10:36:10

如明境 发表于 2022-5-10 10:25
好的，我尝试了一下用append，好像可以解决我的问题

你要想获取到 ["123","234","456","567","789","890"] 的话就这样

glds = [{"a":123,"b":234,"c":345},{"a":456,"b":567,"c":678},{"a":789,"b":890,"c":910}]
gid = []
for gld in glds:
    gid.append(f"{gld['a']}")
    gid.append(f"{gld['b']}")
print(gid)

跳转到最佳答案楼层

isdkz

glds = [{"a":1,"b":2,"c":3},{"a":4,"b":5,"c":6},{"a":7,"b":8,"c":9}]
gid = []
for gld in glds:
    gid.append(f"{gld['a']},{gld['b']}")
print(gid)

如明境

isdkz 发表于 2022-5-10 10:11

glds = [{"a":123,"b":234,"c":345},{"a":456,"b":567,"c":678},{"a":789,"b":890,"c":910}]
gid = []
for gld in glds:
    gid.extend(f'{gld["a"]}{gld["b"]}')
print(gid)

不过这个有一个问题，就是会把获取到的值全部拆分，有没有什么办法获取到完整的值呢
这是获取到的值：['1', '2', '3', '2', '3', '4', '4', '5', '6', '5', '6', '7', '7', '8', '9', '8', '9', '0']
我想获取的值是：['123","234","456","567","789","890"]

isdkz

如明境 发表于 2022-5-10 10:19
不过这个有一个问题，就是会把获取到的值全部拆分，有没有什么办法获取到完整的值呢
这是获取到的值： ...

你先把我的代码复制过去看看效果先，

你那个会拆分是因为你用了 extend

如明境

isdkz 发表于 2022-5-10 10:21
你先把我的代码复制过去看看效果先，

你那个会拆分是因为你用了 extend

好的，我尝试了一下用append，好像可以解决我的问题

isdkz

如明境 发表于 2022-5-10 10:25
好的，我尝试了一下用append，好像可以解决我的问题

你要想获取到 ["123","234","456","567","789","890"] 的话就这样

glds = [{"a":123,"b":234,"c":345},{"a":456,"b":567,"c":678},{"a":789,"b":890,"c":910}]
gid = []
for gld in glds:
    gid.append(f"{gld['a']}")
    gid.append(f"{gld['b']}")
print(gid)

如明境

isdkz 发表于 2022-5-10 10:36
你要想获取到 ["123","234","456","567","789","890"] 的话就这样

谢谢