[已解决]SyntaxError: 'break' outside the loop

Boibot

# This is a guess the number game.
import random

print('Hello. What is your name?')
name = input()

print('Well, ' + name + ',I am thinking a number between 1 and 20.')
secretNumber = random.randint(1,20)

# print('Debug: Secret number is ' + str(secretNumber))

for guessesTaken in range(1,7):
    print('Take a guess.')
    guess = int(input())
    try:
        if guess < secretNumber:
            print('Your guess is too low.')
        elif guess > secretNumber:
            print('Your guess is too high.')
        else:
            break # This condition is for the correct guess!
    except ValueError:
        print('You did not enter a number.')
   
if guess == secretNumber:
    print('Good job, ' + name + '! You guessed my number in ' +str(guessesTaken) +' guesses!')
else:
    print('Nope. The number I was thinking of was ' + str(secretNumber))

最佳答案

月排行榜 / 总排行榜

Twilight6

2022-5-12 07:16:34

Boibot 发表于 2022-5-11 23:52
我用pythontutor检验这段代码，指出SyntaxError: 'break' outside the loop
我用F5跑一下，抛出来
这样ex ...

这个报错是因为你 guess 那输入的是字符串 'ss' ，而 'ss' 在 try 捕获外，导致没有捕获到这个  ValueError

而且建议在循环之前对数值进行初始化，这样可以更安全的执行代码，参考代码：

1. # This is a guess the number game.
   
2. import random
   
3. 
   
4. print('Hello. What is your name?')
   
5. name = input()
   
6. 
   
7. print('Well, ' + name + ',I am thinking a number between 1 and 20.')
   
8. secretNumber = random.randint(1, 20)
   
9. 
   
10. # print('Debug: Secret number is ' + str(secretNumber))
    
11. guess = 0
    
12. guessesTaken = 0
    
13. for guessesTaken in range(1, 7):
    
14.     print('Take a guess.')
    
15.     try:
    
16.         guess = int(input())
    
17.         if guess < secretNumber:
    
18.             print('Your guess is too low.')
    
19.         elif guess > secretNumber:
    
20.             print('Your guess is too high.')
    
21.         else:
    
22.             break  # This condition is for the correct guess!
    
23.     except ValueError:
    
24.         print('You did not enter a number.')
    
25. 
    
26. if guess == secretNumber:
    
27.     print('Good job, ' + name + '! You guessed my number in ' + str(guessesTaken) + ' guesses!')
    
28. else:
    
29.     print('Nope. The number I was thinking of was ' + str(secretNumber))

复制代码

跳转到最佳答案楼层

Twilight6

SyntaxError: 'break' outside the loop

这个报错主要是指你在非循环体中使用了 break 关键字

只要将 break 关键字都使用在循环内即可

你代码中并没有发现会抛出这个错误的问题

isdkz

你这个没有问题，标题那个错误是在 break 没有放在循环里面才会出现的

Boibot

我用pythontutor检验这段代码，指出SyntaxError: 'break' outside the loop
我用F5跑一下，抛出来

1. line 14, in <module>
   
2.     guess = int(input())
   
3. ValueError: invalid literal for int() with base 10: 'ss'

复制代码

这样except ValueError等于没有设置

Boibot

Twilight6 发表于 2022-5-11 23:45
这个报错主要是指你在非循环体中使用了 break 关键字

只要将 break 关键字都使用在循环内即可

请往下翻一下

Boibot

isdkz 发表于 2022-5-11 23:45
你这个没有问题，标题那个错误是在 break 没有放在循环里面才会出现的

请往下翻一下

Twilight6

Boibot 发表于 2022-5-11 23:52
我用pythontutor检验这段代码，指出SyntaxError: 'break' outside the loop
我用F5跑一下，抛出来
这样ex ...

这个报错是因为你 guess 那输入的是字符串 'ss' ，而 'ss' 在 try 捕获外，导致没有捕获到这个  ValueError

而且建议在循环之前对数值进行初始化，这样可以更安全的执行代码，参考代码：

1. # This is a guess the number game.
   
2. import random
   
3. 
   
4. print('Hello. What is your name?')
   
5. name = input()
   
6. 
   
7. print('Well, ' + name + ',I am thinking a number between 1 and 20.')
   
8. secretNumber = random.randint(1, 20)
   
9. 
   
10. # print('Debug: Secret number is ' + str(secretNumber))
    
11. guess = 0
    
12. guessesTaken = 0
    
13. for guessesTaken in range(1, 7):
    
14.     print('Take a guess.')
    
15.     try:
    
16.         guess = int(input())
    
17.         if guess < secretNumber:
    
18.             print('Your guess is too low.')
    
19.         elif guess > secretNumber:
    
20.             print('Your guess is too high.')
    
21.         else:
    
22.             break  # This condition is for the correct guess!
    
23.     except ValueError:
    
24.         print('You did not enter a number.')
    
25. 
    
26. if guess == secretNumber:
    
27.     print('Good job, ' + name + '! You guessed my number in ' + str(guessesTaken) + ' guesses!')
    
28. else:
    
29.     print('Nope. The number I was thinking of was ' + str(secretNumber))

复制代码

Boibot

Twilight6 发表于 2022-5-12 07:16
这个报错是因为你 guess 那输入的是字符串 'ss' ，而 'ss' 在 try 捕获外，导致没有捕获到这个  ValueE ...

怎么改写能让try捕获'ss'异常

Boibot

Twilight6 发表于 2022-5-12 07:16
这个报错是因为你 guess 那输入的是字符串 'ss' ，而 'ss' 在 try 捕获外，导致没有捕获到这个  ValueE ...

怎么改写能让try捕获'ss'异常

Twilight6

Boibot 发表于 2022-5-12 14:51
怎么改写能让try捕获'ss'异常

6 楼的代码就可以