[已解决]SyntaxError: 'break' outside the loop

Boibot

# This is a guess the number game.
import random

print('Hello. What is your name?')
name = input()

print('Well, ' + name + ',I am thinking a number between 1 and 20.')
secretNumber = random.randint(1,20)

# print('Debug: Secret number is ' + str(secretNumber))

for guessesTaken in range(1,7):
    print('Take a guess.')
    guess = int(input())
    try:
        if guess < secretNumber:
            print('Your guess is too low.')
        elif guess > secretNumber:
            print('Your guess is too high.')
        else:
            break # This condition is for the correct guess!
    except ValueError:
        print('You did not enter a number.')
   
if guess == secretNumber:
    print('Good job, ' + name + '! You guessed my number in ' +str(guessesTaken) +' guesses!')
else:
    print('Nope. The number I was thinking of was ' + str(secretNumber))

最佳答案

月排行榜 / 总排行榜

Twilight6

2022-5-12 07:16:34

Boibot 发表于 2022-5-11 23:52
我用pythontutor检验这段代码，指出SyntaxError: 'break' outside the loop
我用F5跑一下，抛出来
这样ex ...

这个报错是因为你 guess 那输入的是字符串 'ss' ，而 'ss' 在 try 捕获外，导致没有捕获到这个  ValueError

而且建议在循环之前对数值进行初始化，这样可以更安全的执行代码，参考代码：

# This is a guess the number game.
import random

print('Hello. What is your name?')
name = input()

print('Well, ' + name + ',I am thinking a number between 1 and 20.')
secretNumber = random.randint(1, 20)

# print('Debug: Secret number is ' + str(secretNumber))
guess = 0
guessesTaken = 0
for guessesTaken in range(1, 7):
    print('Take a guess.')
    try:
        guess = int(input())
        if guess < secretNumber:
            print('Your guess is too low.')
        elif guess > secretNumber:
            print('Your guess is too high.')
        else:
            break  # This condition is for the correct guess!
    except ValueError:
        print('You did not enter a number.')

if guess == secretNumber:
    print('Good job, ' + name + '! You guessed my number in ' + str(guessesTaken) + ' guesses!')
else:
    print('Nope. The number I was thinking of was ' + str(secretNumber))

跳转到最佳答案楼层

Twilight6

SyntaxError: 'break' outside the loop

这个报错主要是指你在非循环体中使用了 break 关键字

只要将 break 关键字都使用在循环内即可

你代码中并没有发现会抛出这个错误的问题

isdkz

你这个没有问题，标题那个错误是在 break 没有放在循环里面才会出现的

Boibot

我用pythontutor检验这段代码，指出SyntaxError: 'break' outside the loop
我用F5跑一下，抛出来

line 14, in <module>
    guess = int(input())
ValueError: invalid literal for int() with base 10: 'ss'

这样except ValueError等于没有设置

Boibot

Twilight6 发表于 2022-5-11 23:45
这个报错主要是指你在非循环体中使用了 break 关键字

只要将 break 关键字都使用在循环内即可

请往下翻一下

Boibot

isdkz 发表于 2022-5-11 23:45
你这个没有问题，标题那个错误是在 break 没有放在循环里面才会出现的

请往下翻一下

Twilight6

Boibot 发表于 2022-5-11 23:52
我用pythontutor检验这段代码，指出SyntaxError: 'break' outside the loop
我用F5跑一下，抛出来
这样ex ...

这个报错是因为你 guess 那输入的是字符串 'ss' ，而 'ss' 在 try 捕获外，导致没有捕获到这个  ValueError

而且建议在循环之前对数值进行初始化，这样可以更安全的执行代码，参考代码：

# This is a guess the number game.
import random

print('Hello. What is your name?')
name = input()

print('Well, ' + name + ',I am thinking a number between 1 and 20.')
secretNumber = random.randint(1, 20)

# print('Debug: Secret number is ' + str(secretNumber))
guess = 0
guessesTaken = 0
for guessesTaken in range(1, 7):
    print('Take a guess.')
    try:
        guess = int(input())
        if guess < secretNumber:
            print('Your guess is too low.')
        elif guess > secretNumber:
            print('Your guess is too high.')
        else:
            break  # This condition is for the correct guess!
    except ValueError:
        print('You did not enter a number.')

if guess == secretNumber:
    print('Good job, ' + name + '! You guessed my number in ' + str(guessesTaken) + ' guesses!')
else:
    print('Nope. The number I was thinking of was ' + str(secretNumber))

Boibot

Twilight6 发表于 2022-5-12 07:16
这个报错是因为你 guess 那输入的是字符串 'ss' ，而 'ss' 在 try 捕获外，导致没有捕获到这个  ValueE ...

怎么改写能让try捕获'ss'异常

Boibot

Twilight6 发表于 2022-5-12 07:16
这个报错是因为你 guess 那输入的是字符串 'ss' ，而 'ss' 在 try 捕获外，导致没有捕获到这个  ValueE ...

怎么改写能让try捕获'ss'异常

Twilight6

Boibot 发表于 2022-5-12 14:51
怎么改写能让try捕获'ss'异常

6 楼的代码就可以