[已解决]python如何把一个字符串均匀切片？

leafu

已知：data_list=['06091214202810', '09101218293214', '04161819272804', '02060715202115'']
求解：list_1=['06', '09', '12', '14', '20', '28', '10','09', '10', '12', '18', '29', '32', '14', '04', '16', '18', '19', '27', '28', '04', '02','06', '07', '15', '20',' 21', '15']
是的，没猜错，就是爬取的最近几期彩票的开奖码，可惜是开过的55555
现在的问题是，我需要把'06091214202810'，分解成['06', '09', '12', '14', '20', '28', '10'],大佬们有没有简短的好方法？因为后续我打算每期开奖码以期号单独为一个变量，例如：issue_2022103 = ['06', '09', '12', '14', '20', '28', '10'],靠我这个方法顶不住哇。
目前方式：
    list_1 = []
    for i in data_list:
        list_1.append(int(i[0:2]))
        list_1.append(int(i[2:4]))
        list_1.append(int(i[4:6]))
        list_1.append(int(i[6:8]))
        list_1.append(int(i[8:10]))
        list_1.append(int(i[10:12]))
        list_1.append(int(i[12:14]))
    print(list_1)

最佳答案

月排行榜 / 总排行榜

cflying

2022-9-8 15:26:41

import re
data_list=['06091214202810', '09101218293214', '04161819272804', '02060715202115']
for i in data_list:
    print(re.findall('\d{2}',i))
或者这种也行
import re
data_list=['06091214202810', '09101218293214', '04161819272804', '02060715202115']
print(re.findall('\d{2}',str(data_list)))

自己改成list即可

跳转到最佳答案楼层

cflying

import re
data_list=['06091214202810', '09101218293214', '04161819272804', '02060715202115']
for i in data_list:
    print(re.findall('\d{2}',i))
或者这种也行
import re
data_list=['06091214202810', '09101218293214', '04161819272804', '02060715202115']
print(re.findall('\d{2}',str(data_list)))

自己改成list即可

高山

本帖为转载帖
见https://blog.csdn.net/qdPython/article/details/105751520

Twilight6

可以这样：

data_list = ['06091214202810', '09101218293214', '04161819272804', '02060715202115']
ist_1 = []
for i in data_list:
    for j in range(0, len(i), 2):
        ist_1.append(i[j:j+2])
print(ist_1)

列表推导式简化代码：

data_list = ['06091214202810', '09101218293214', '04161819272804', '02060715202115']
ist_1 = [i[j:j+2] for i in data_list for j in range(0, len(i), 2)]
print(ist_1)

月下孤井

data_list = ['06091214202810', '09101218293214', '04161819272804', '02060715202115']
list_1 = [k[i*2:i*2+2] for k in data_list for i in range(int(len(k)/2))]
print(list_1)