[已解决]简化三元表达出错

jcpython2

name = input().split()
c = []
for i in range(3):
    c.append(name[i])
c = tuple(c)
print(c)

c = tuple(c.append(name[i]) for i in range(3))

简化后输出none

(None, None, None)

最佳答案

月排行榜 / 总排行榜

ba21

2022-10-5 22:53:53

c = [neme[i] for i in range(3)]

跳转到最佳答案楼层

ba21

c = [neme[i] for i in range(3)]

jcpython2

ba21 发表于 2022-10-5 22:53
c = [neme for i in range(3)]

thx
再问多个
为啥

c = [name[i] for i in range(3)]

默认出来是list
但如果把大括号改为括号他不会自动转tuple，而是报错呢
想不报错只能是

c = tuple(name[i] for i in range(3))

ba21

jcpython2 发表于 2022-10-5 23:05
thx
再问多个
为啥

列表推导式

c = tuple([neme[i] for i in range(3)])