[已解决]这个for循环怎么破？？想半天想不出

13978074582

1. 
   
2. 
   
3. from itertools import combinations
   
4. a = [1,2,3,4,5,6,7]
   
5. def aa():
   
6.     return list(combinations(a,6))
   
7. ss = aa()
   
8. for i in ss:
   
9.     print(i)
   
10. 
    

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这段代码会打印7个元组。。。插入什么代码可以让他们。。每打印一次加一个空行。。每打印5次加一行"==============="
脑子不够用了！！

最佳答案

月排行榜 / 总排行榜

tommyyu

2022-10-28 17:18:42

1. 
   
2. 
   
3. from itertools import combinations
   
4. a = [1,2,3,4,5,6,7]
   
5. def aa():
   
6.     return list(combinations(a,6))
   
7. ss = aa()
   
8. count = 0
   
9. for i in ss:
   
10.     count += 1
    
11.     print(i)
    
12.     print()
    
13.     if count == 5:
    
14.         print('===============')
    
15.         count = 0
    

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tommyyu

1. 
   
2. 
   
3. from itertools import combinations
   
4. a = [1,2,3,4,5,6,7]
   
5. def aa():
   
6.     return list(combinations(a,6))
   
7. ss = aa()
   
8. count = 0
   
9. for i in ss:
   
10.     count += 1
    
11.     print(i)
    
12.     print()
    
13.     if count == 5:
    
14.         print('===============')
    
15.         count = 0
    

复制代码

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