[已解决]列表套列表怎么转变成数据帧，求大师帮忙

futui

先谢谢大侠，下面是我的需求：


webpage.txt文本内容如下：
var r = [["000001","HXCZHH","华夏成长混合","混合型-灵活","HUAXIACHENGZHANGHUNHE"],["000002","HXCZHH","华夏成长混合(后端)","混合型-灵活","HUAXIACHENGZHANGHUNHE"],["000003","ZHKZZZQA","中海可转债债券A","债券型-可转债","ZHONGHAIKEZHUANZHAIZHAIQUANA"],["980003","TPYLGYGDCYZ","太平洋六个月滚动持有债","债券型-长债","TAIPINGYANGLIUGEYUEGUNDONGCHIYOUZHAI"]];


我想用下面方法提取列表：
with open(r'C:\Users\ppp\Desktop\webpage.txt', "r") as f:      
    #print(type(f))
    response  = f.read()

data_list = re.findall(r'\[(.*?)\]',response)


上面这个方法提不出，要怎么才能从桌面文本webpage.txt中 ，提取出列表data_list：
data_list = [["000001","HXCZHH","华夏成长混合","混合型-灵活","HUAXIACHENGZHANGHUNHE"],["000002","HXCZHH","华夏成长混合(后端)","混合型-灵活","HUAXIACHENGZHANGHUNHE"],["000003","ZHKZZZQA","中海可转债债券A","债券型-可转债","ZHONGHAIKEZHUANZHAIZHAIQUANA"],["980003","TPYLGYGDCYZ","太平洋六个月滚动持有债","债券型-长债","TAIPINGYANGLIUGEYUEGUNDONGCHIYOUZHAI"]]


df = pd.dataframe(data_list,columns=["代码" ,"名称首字拼音","名称","类型", "其它"])

我最终要的结果是下面这个样子：
代码               名称首字拼音    名称             类型                                            其它                                 
"000001"   HXCZHH"            "华夏成长混合"                  "混合型-灵活"      "HUAXIACHENGZHANGHUNHE"
"000002"  "HXCZHH"            "华夏成长混合(后端)"         "混合型-灵活"      "HUAXIACHENGZHANGHUNHE"
"000003"  ZHKZZZQA"          "中海可转债债券A"             "债券型-可转债"   "ZHONGHAIKEZHUANZHAIZHAIQUANA"
"980003"  "TPYLGYGDCYZ"   "太平洋六个月滚动持有债"   "债券型-长债"      "TAIPINGYANGLIUGEYUEGUNDONGCHIYOUZHAI"

最佳答案

月排行榜 / 总排行榜

isdkz

2023-3-27 18:56:05

1. import re
   
2. import pandas as pd
   
3. 
   
4. with open(r'C:\Users\ppp\Desktop\webpage.txt', "r") as f:      
   
5.     #print(type(f))
   
6.     response  = f.read()
   
7. 
   
8. data_list = re.findall(r'\[(?:.*)\]', response)
   
9. 
   
10. df = pd.DataFrame(data_list[0], columns=["代码" ,"名称首字拼音","名称","类型", "其它"])

复制代码

跳转到最佳答案楼层

isdkz

1. import re
   
2. import pandas as pd
   
3. 
   
4. with open(r'C:\Users\ppp\Desktop\webpage.txt', "r") as f:      
   
5.     #print(type(f))
   
6.     response  = f.read()
   
7. 
   
8. data_list = re.findall(r'\[(?:.*)\]', response)
   
9. 
   
10. df = pd.DataFrame(data_list[0], columns=["代码" ,"名称首字拼音","名称","类型", "其它"])

复制代码

futui

大师，不知什么原因，报错

Traceback (most recent call last):
  File "D:\Synchronization\OneDrive\Investment\Accounts\python\test_temp\temp_test.py", line 10, in <module>
    df = pd.DataFrame(data_list[0], columns=["代码" ,"名称首字拼音","名称","类型", "其它"])
  File "C:\Users\cenghua\anaconda3\lib\site-packages\pandas\core\frame.py", line 756, in __init__
    raise ValueError("DataFrame constructor not properly called!")
ValueError: DataFrame constructor not properly called!