[已解决]请大师帮忙形成pd数据帧，谢谢

futui

data = '''Query112307719530320351087_1671530759948({"rc":0,"rt":22,"svr":181216787,"lt":1,"full":0,"dlmkts":"","data":{"code":"000001","market":1,"name":"上证指数","klines":["2022-11-10,-34451102208.0,28253458432.0,6197641216.0,-18004312064.0,-16446790144.0,-4.09,3.35,0.74,-2.14,-1.95,3036.13,-0.39,10908.55,-1.33","2022-11-11,2016566784.0,12980424704.0,-14996992000.0,-10999246848.0,13015813632.0,0.16,1.06,-1.23,-0.90,1.06,3087.29,1.69,11139.77,2.12","2022-11-14,-30351907584.0,23198273536.0,7153635328.0,-14855168000.0,-15496739584.0,-2.84,2.17,0.67,-1.39,-1.45,3083.40,-0.13,11113.46,-0.24]}});'''
data_str = re.findall(r'(\{.*\})',response)[0] #提出数据
data_json = json.loads(data_str)['data']['klines']
data_list = data_json.split('","',')    #？？？？？
df = pd.DataFrame([data_json])
print(df)

出来只一列，我需要以日期为界成一个列表，出现三行多列
即要把日期前面","》这个为分界，行成多个列表
请大师指导修改代码，谢谢

最佳答案

月排行榜 / 总排行榜

isdkz

2023-4-11 11:12:47

从给定的数据来看，您需要将data_json变量中的字符串分割成多个列表，并将这些列表作为DataFrame的行。这是一个修改后的代码：

import re
import json
import pandas as pd

data = '''Query112307719530320351087_1671530759948({"rc":0,"rt":22,"svr":181216787,"lt":1,"full":0,"dlmkts":"","data":{"code":"000001","market":1,"name":"上证指数","klines":["2022-11-10,-34451102208.0,28253458432.0,6197641216.0,-18004312064.0,-16446790144.0,-4.09,3.35,0.74,-2.14,-1.95,3036.13,-0.39,10908.55,-1.33","2022-11-11,2016566784.0,12980424704.0,-14996992000.0,-10999246848.0,13015813632.0,0.16,1.06,-1.23,-0.90,1.06,3087.29,1.69,11139.77,2.12","2022-11-14,-30351907584.0,23198273536.0,7153635328.0,-14855168000.0,-15496739584.0,-2.84,2.17,0.67,-1.39,-1.45,3083.40,-0.13,11113.46,-0.24]}});'''
data_str = re.findall(r'(\{.*\})', data)[0]  # 提出数据
data_json = json.loads(data_str)['data']['klines']

# 分割字符串，创建多个列表
data_list = [x.split(',') for x in data_json]

# 将列表作为DataFrame的行
df = pd.DataFrame(data_list)

print(df)

现在，您的DataFrame将包含3行和15列，如您所期望的。

跳转到最佳答案楼层

isdkz

从给定的数据来看，您需要将data_json变量中的字符串分割成多个列表，并将这些列表作为DataFrame的行。这是一个修改后的代码：

import re
import json
import pandas as pd

data = '''Query112307719530320351087_1671530759948({"rc":0,"rt":22,"svr":181216787,"lt":1,"full":0,"dlmkts":"","data":{"code":"000001","market":1,"name":"上证指数","klines":["2022-11-10,-34451102208.0,28253458432.0,6197641216.0,-18004312064.0,-16446790144.0,-4.09,3.35,0.74,-2.14,-1.95,3036.13,-0.39,10908.55,-1.33","2022-11-11,2016566784.0,12980424704.0,-14996992000.0,-10999246848.0,13015813632.0,0.16,1.06,-1.23,-0.90,1.06,3087.29,1.69,11139.77,2.12","2022-11-14,-30351907584.0,23198273536.0,7153635328.0,-14855168000.0,-15496739584.0,-2.84,2.17,0.67,-1.39,-1.45,3083.40,-0.13,11113.46,-0.24]}});'''
data_str = re.findall(r'(\{.*\})', data)[0]  # 提出数据
data_json = json.loads(data_str)['data']['klines']

# 分割字符串，创建多个列表
data_list = [x.split(',') for x in data_json]

# 将列表作为DataFrame的行
df = pd.DataFrame(data_list)

print(df)

现在，您的DataFrame将包含3行和15列，如您所期望的。