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发表于 2023-12-6 00:38:17
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嗨,初学者!让我们一起来解决这个问题。首先,我们需要使用Python的random模块生成十个点,每个点包含一个id和x、y坐标。
- import random
- points = []
- for i in range(10):
- point_id = i + 1
- x = random.randint(0, 100)
- y = random.randint(0, 100)
- points.append((point_id, x, y))
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接下来,我们需要计算所有点之间的距离。我们可以使用两点间的欧氏距离公式来计算两点之间的距离。
- import math
- def calculate_distance(point1, point2):
- x1, y1 = point1[1], point1[2]
- x2, y2 = point2[1], point2[2]
- distance = math.sqrt((x2 - x1) ** 2 + (y2 - y1) ** 2)
- return distance
- distances = {}
- for i in range(len(points)):
- for j in range(i + 1, len(points)):
- point1 = points[i]
- point2 = points[j]
- distance = calculate_distance(point1, point2)
- distances[(point1[0], point2[0])] = distance
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最后,我们需要找到距离最近的两个点及其距离。我们可以使用min函数来找到字典中最小的值,并返回对应的键。
- closest_points = min(distances, key=distances.get)
- closest_distance = distances[closest_points]
- print("距离最近的两个点的id是{}和{},它们的距离是{}".format(closest_points[0], closest_points[1], closest_distance))
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这样就完成了!完整代码如下:
- import random
- import math
- def calculate_distance(point1, point2):
- x1, y1 = point1[1], point1[2]
- x2, y2 = point2[1], point2[2]
- distance = math.sqrt((x2 - x1) ** 2 + (y2 - y1) ** 2)
- return distance
- points = []
- for i in range(10):
- point_id = i + 1
- x = random.randint(0, 100)
- y = random.randint(0, 100)
- points.append((point_id, x, y))
- distances = {}
- for i in range(len(points)):
- for j in range(i + 1, len(points)):
- point1 = points[i]
- point2 = points[j]
- distance = calculate_distance(point1, point2)
- distances[(point1[0], point2[0])] = distance
- closest_points = min(distances, key=distances.get)
- closest_distance = distances[closest_points]
- print("距离最近的两个点的id是{}和{},它们的距离是{}".format(closest_points[0], closest_points[1], closest_distance))
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希望这可以帮到你!如果还有其他问题,请随时提问。
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