小甲鱼作业：计算今天是今年的第几天。。。

18326638710

1. 
   
2. #include <stdio.h>
   
3. 
   
4. void main()
   
5. {
   
6. int month, d, day, year, leap;
   
7. printf("please a date: \n");
   
8. scanf("%d %d %d",&year, &month, &d);
   
9. if ( year % 4 == 0 )
   
10. {
    
11. if ( year % 100 == 0 )
    
12. {
    
13. if ( year % 400 == 0 )
    
14. {
    
15. leap = 1;
    
16. }
    
17. else leap = 1;
    
18. }
    
19. }
    
20. else leap = 0;
    
21. if ( leap )
    
22. {
    
23. if ( month > 3 )
    
24. {
    
25. day = 31;
    
26. printf("This is %d year %d days\n", year,(month-1)*31+d);pause;
    
27. }
    
28. else if ( month = 2 )
    
29. {
    
30. day = 28;
    
31. printf("This is %d year %d days\n", year,31+d);pause;
    
32. }
    
33. }else
    
34. switch (month)
    
35. {
    
36. case 1: printf("This is %d year %d days\n", year,d); break;
    
37. case 2: printf("This is %d year %d days\n", year,31+d); break;
    
38. case 3: printf("This is %d year %d days\n", year,61+d); break;
    
39. case 4: printf("This is %d year %d days\n", year,2*31+30+d); break;
    
40. case 5: printf("This is %d year %d days\n", year,2*(30+31)+d); break;
    
41. case 6: printf("This is %d year %d days\n", year,3*31+2*30+d); break;
    
42. case 7: printf("This is %d year %d days\n", year,3*(30+31)+d); break;
    
43. case 8: printf("This is %d year %d days\n", year,4*31+3*30+d); break;
    
44. case 9: printf("This is %d year %d days\n", year,5*31+3*30+d); break;
    
45. case 10: printf("This is %d year %d days\n", year,5*31+4*30+d); break;
    
46. case 11: printf("This is %d year %d days\n", year,6*31+4*30+d); break;
    
47. case 12: printf("This is %d year %d days\n", year,6*31+5*30+d); break;
    
48. default: printf("input error!!!!!\n");
    
49. }
    
50. 
    
51. }

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这是我写的代码，我觉得代码量太多了，关于这个问题能有好的办法么？？请大神帮忙。。。这是小甲鱼视频里的题目。。

仰望天上的光

1. #include<stdio.h>
   
2. int main(void) {
   
3.     int year,month,day,days,i,d;
   
4.         printf("please a date: \n");       
   
5.         scanf("%d %d %d",&year, &month, &day);       
   
6.     days=0;
   
7.     for(i=1;i<month;i++) {
   
8.         switch(i) {
   
9.                 case 1: case 3: case 5:
   
10.                 case 7: case 8: case 10:
    
11.                 case 12:d=31;break;
    
12.                 case 4: case 6: case 9:
    
13.                 case 11:d=30;break;
    
14.                 case 2:d=((year%4==0&&year%100!=0||year%400==0)?29:28);
    
15.         }
    
16.         days+=d;
    
17.     }
    
18.     printf("%d年%d月%d日是这一年的第%d天。\n",year,month,day,days+day);
    
19. }
    

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18326638710

仰望天上的光 发表于 2013-11-16 21:01

                               
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哦，谢谢。学习了。。。^_^

18326638710

18326638710 发表于 2013-11-16 21:49

                               
登录/注册后可看大图

哦，谢谢。学习了。。。^_^

E:\test.jpg

下弦月之夜_夜末

//求今天是今年的第几天
#include "stdio.h"
int main(void)
{
        int a[12]={31,28,31,30,31,30,31,31,30,31,30,31},i,yue,ri,sum=0;
        printf("请输入月份：");
        scanf("%d",&yue);
        printf("请输入日数：");
        scanf("%d",&ri);
        for(i=0;i<yue;i++)
                sum=sum+a;
        printf("今天是今年的第%d天",(sum+ri));
        return 0;
}

下弦月之夜_夜末

#include<stdio.h>
int main(void) {
    int year,month,day,days,i,d;
        printf("please a date: \n");        
        scanf("%d %d %d",&year, &month, &day);        
    days=0;
    for(i=1;i<=month;i++)   //mouth前面应该加个=
        {
        switch(i)
                {
                case 1:
                                case 3:
                                case 5:
                case 7:
                                case 8:
                                case 10:
                case 12:d=31;break;
                case 4:
                                case 6:
                                case 9:
                case 11:d=30;break;
                case 2:d=((year%4==0&&year%100!=0||year%400==0)?29:28);
        }
        days+=d;
    }
    printf("%d年%d月%d日是这一年的第%d天。\n",year,month,day,days+day);
return 0;
}

风吹绿野

不错不错，学习了