[已解决]求助，在一个list里面，怎么去除有相同的元素的成分

thyx

我想比如一个list['t1','h1','t2','y5','y6','f6','t7'],只要有相同的数字就可以去除掉，不用管字母是什么，所以结果就应该是['t2','y5','t7'],应该怎么写，求助啊

最佳答案

月排行榜 / 总排行榜

xinshouxuexi

2016-10-31 22:46:33

1. >>> list1 = ['t1','h1','t2','y5','y6','f6','t7','j9','F4','88','I3','-5']
   
2. >>> list2 = [d for d in list1 for c in [b for b in [(list(a) [1])for a in list1] if [(list(a) [1])for a in list1].count(b) == 1] if (list(d)[1]) == c]
   
3. >>> list2
   
4. ['t2', 't7', 'j9', 'F4', '88', 'I3']

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跳转到最佳答案楼层

xinshouxuexi

1. list1 = ['t1','h1','t2','y5','y6','f6','t7']
   
2. list2 = []
   
3. for m in range(len(list1)):
   
4.     for n in range(len(list1)):
   
5.         if m != n:
   
6.                 if list1[n][1] == list1[m][1]:
   
7.                     list2.append(list1[m])
   
8.                     list2.append(list1[n])
   
9. list3 = list(set(list2))
   
10. list4 = list3+list1
    
11. list5 = [x for x in list4 if list4.count(x) ==1]
    
12. print(list5)

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SixPy

1. >>> ls = ['t1','h1','t2','y5','y6','f6','t7']
   
2. >>> cntr = {}
   
3. >>> for x in ls:
   
4.         cntr.setdefault(x[-1],[])
   
5.         cntr[x[-1]].append(x)       
   
6. 
   
7. >>> [cntr[x][0] for x in cntr if len(cntr[x])==1]
   
8. ['t7', 't2', 'y5']

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jackie23cn

filter

xinshouxuexi

1. >>> list1 = ['t1','h1','t2','y5','y6','f6','t7','j9','F4','88','I3','-5']
   
2. >>> list2 = [d for d in list1 for c in [b for b in [(list(a) [1])for a in list1] if [(list(a) [1])for a in list1].count(b) == 1] if (list(d)[1]) == c]
   
3. >>> list2
   
4. ['t2', 't7', 'j9', 'F4', '88', 'I3']

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