Python：每日一题 95（答题领鱼币）

冬雪雪冬

有一个多行的字符串，要给每行的开头加上数字，这个数字代表其后紧接着的与本行内容相同的行数。例如

FishC
FishC
FishC
FishC
Little turtle
Little turtle
Python
FishC

结果为

(3)FishC
(2)FishC
(1)FishC
(0)FishC
(1)Little turtle
(0)Little turtle
(0)Python
(0)FishC

我的解法：

游客，如果您要查看本帖隐藏内容请回复

baicel21314

how happy to this

sunnychou

BngThea

def addhead(list1):
    count = 0
    for i in range(0,len(list1)):
        for j in range(i + 1,len(list1)):
            if list1[j] == list1[i]:
                count += 1
        print('(' + str(count) + ')' + list1[i])
        count = 0


list2 = ['FishC', 'FishC', 'FishC', 'FishC', 'Little turtle', 'Little turtle', 'Python', 'FishC']
addhead(list2)
        

白牙

list0= ['FishC', 'FishC', 'FishC', 'FishC', 'Little turtle', 'Little turtle', 'Python', 'FishC']
fuben_list=list0.split(',')
next = list1[-1]
list[-1]='(0)'+list1[-1]
for i in range(-2,-len(list1)-1,-1):
    if list1[i]==next:
        count+=1
    else:
        count=0
    next=list1[i]
    list0[i]='(%d)'%conut+list[i]
print('\n'.join(list1))

一条漂浮的枫叶

学习一下

bush牛

from itertools import groupby
a = '''
FishC
FishC
FishC
FishC
Little turtle
Little turtle
Python
FishC
'''
s = [i for i in a.split('\n') if i != '']
b = [list(g) for k, g in groupby(s)]
for i in range(len(b)):
    for j in range(len(b[i])):
        print(len(b[i])-1-j,b[i][j])

sky

print("\n".join(f"({s[i+1:].count(c)}){c}" for i,c in enumerate(s)))

你看我屌不屌
py3.6以上

ChrisYang

s='''FishC
FishC
FishC
FishC
Little turtle
Little turtle
Python\nFishC'''
ss=s.split('\n')
t=[]#全是0
for i in range(len(ss)):
    t.append(0)


for i in range(1,len(ss)):   
    if ss[-i-1]==ss[-i]:
        t[-i-1]=1+t[-i]
        
for i in range(len(ss)):
    print("("+str(t[i])+")"+str(ss[i]))

————————————————————————————————
运行结果
===================== RESTART: D:\Python36-32\caogao.py =====================
(3)FishC
(2)FishC
(1)FishC
(0)FishC
(1)Little turtle
(0)Little turtle
(0)Python
(0)FishC
>>> 

BngThea

def addhead(list1):
    count = 0
    for i in range(0,len(list1)):
        for j in range(i + 1,len(list1)):
            if list1[j] == list1[i]:
                count += 1
            else:
                break
        print('(' + str(count) + ')' + list1[i])
        count = 0


list2 = ['FishC', 'FishC', 'FishC', 'FishC', 'Little turtle', 'Little turtle', 'Python', 'FishC']
addhead(list2)

之前没看到题目要求是紧跟着的

jerryxjr1220

from itertools import groupby
[print('(%d)%s' % (i, m)) for m,n in groupby(str1.split('\n')) for i in range(len(list(n))-1,-1,-1)]

solomonxian

按换行符拆分，分组，按成员的数量贴上数字，再拼接起来

import itertools as it

def fun(s):
    lst = ["".join(("(%d)"%k, i,"\n")) for i,j in it.groupby(s.split('\n')) for k in range(len(list(j))-1,-1,-1)]
    return "".join(lst)[:-1]

ChrisYang

哈哈，天天都有鱼币那

wc365

a = '''
FishC
FishC
FishC
FishC
Little turtle
Little turtle
Python
FishC
'''
list1 = a.split(sep='\n')[1:-1]
list2 = ['(0)' + list1[-1]]
for i in range(2,len(list1)+1):
    if list1[-i] != list1[-i+1]:
        list2.append('(0)' + list1[-i])
        n = 0
    else:
        n += 1
        list2.append('('+str(n)+')'+list1[-i])
for each in list2[::-1]:
    print(each)

醉挽丶南风

s1='''FishC
FishC
FishC
FishC
Little turtle
Little turtle
Python
FishC'''
s1=s1.split('\n')
num=len(s1)
for i in range(num):
    count=0
    for j in range(i+1,num):
        if s1[i]==s1[j]:
            count+=1
        else:
            break
    s1[i]='('+str(count)+')'+s1[i]
print('\n'.join(s1))

mintaka

def num(list,n):
    m=0
    if n==len(list)-1:
        return m
    for i in range(n+1,len(list)):
        if list[i]==list[n]:
            m+=1
        else:
            return m


list='''FishC
FishC
FishC
FishC
Little turtle
Little turtle
Python
FishC'''
list=list.split('\n')
for i in range(0,len(list)):
      print '('+str(num(list,i))+')'+list[i]

樱花冷雨

(3)FishC
(2)FishC
(1)FishC
(0)FishC
(1)Little turtle
(0)Little turtle
(0)Python
(0)FishC
为什么FishC有两个0？
怎样换成升（降）序不要零？

左手十字

 words='''Fishc
Fishc
Fishc
Fishc
Little turtle
Little turtle
Python
FishC'''
from collections import Counter
ss= dict(Counter(words.split('\n')))
for keys in ss:
        for i in range(ss[keys]):
                print('(%s)'%str(ss[keys]-i-1),keys)

结果

(3) Fishc
(2) Fishc
(1) Fishc
(0) Fishc
(1) Little turtle
(0) Little turtle
(0) Python
(0) FishC

苏格拉顶

strVal = """
    FishC
    FishC
    FishC
    FishC
    Little turtle
    Little turtle
    Python
    FishC
"""
newStrVal = strVal.split('\n')
strlist = [value.strip() for value in newStrVal if value.strip() is not '']
length = len(strlist)

for i in range(length):
    j = i+1 if i+1<length else length
    n = 0
    for j in range(j,length):
        if strlist[i] == strlist[j]:
            n += 1
        else:
            break
    print("(%d)%s" % (n,strlist[i]))

Greenland

def counteRepeatedLines(string):
    '给多行字符串的每行开头加上紧随其后重复的行数'
    counter = 0
    lines = []
    splits = string.split('\n')
    for i in range(len(splits)):
        if i+1 == len(splits) or splits[i] != splits[i+1]:
            while counter > 0:
                lines.append('(%d)'% counter + splits[i])
                counter -= 1
            lines.append('(0)' + splits[i])
        else:
            counter += 1
    return '\n'.join(lines)

print(counteRepeatedLines('FishC\nFishC\nFishC\nFishC\nLittle turtle\nLittle turtle\nPython\nFishC'))