Python：每日一题 95（答题领鱼币）

guoqing3511 · 发表于 2017-9-10 16:47:15

print("1fishc|\n2fishc\n3fishc\n4fishc\n5little turtle\n")

5jj · 发表于 2017-9-10 16:49:39

不知道

AKA2pac · 发表于 2017-9-11 13:50:44

def addhead(list1):
count = 0
for i in range(0,len(list1)):
      for j in range(i + 1,len(list1)):
         if list1[j] == list1[i]:
            count += 1
      print('(' + str(count) + ')' + list1[i])
      count = 0

list2 = ['FishC', 'FishC', 'FishC', 'FishC', 'Little turtle', 'Little turtle', 'Python', 'FishC']
addhead(list2)

741712547 · 发表于 2017-9-11 16:54:10

a = """FishC
FishC
FishC
FishC
Little turtle
Little turtle
Python
FishC"""
list1 = a.split('\n')
list3 = list1.copy()
list3.reverse()
list4 = [0]
list5 = []

changdu = len(list3)
for index in range(1,changdu):
    if list3[index-1] == list3[index]:
        list4.append(1)
        list4[index] = (list4[index]+list4[index-1])
    else:
        list4.append(0)
for index in range(changdu):
    list5.append('('+str(list4[index])+')'+list3[index])
list5.reverse()
for char in list5:
    print(char)

思路是，用两个列表拼接。倒是实现了，但是有点笨办法。

dnwz · 发表于 2017-9-11 18:57:04

strVal = """
    FishC
    FishC
    FishC
    FishC
    Little turtle
    Little turtle
    Python
    FishC
"""
newStrVal = strVal.split('\n')
strlist = [value.strip() for value in newStrVal if value.strip() is not '']
length = len(strlist)

for i in range(length):
    j = i+1 if i+1<length else length
    n = 0
    for j in range(j,length):
        if strlist[i] == strlist[j]:
            n += 1
        else:
            break
    print("(%d)%s" % (n,strlist[i]))

dnwz · 发表于 2017-9-11 18:57:43

lihuayuan · 发表于 2017-9-11 19:39:29

不知道哦

根号三.5 · 发表于 2017-9-11 21:44:45

s1='''FishC
FishC
FishC
FishC
Little turtle
Little turtle
Python
FishC'''
s1=s1.split('\n')
num=len(s1)
for i in range(num):
count=0
for j in range(i+1,num):
      if s1[i]==s1[j]:
         count+=1
      else:
         break
s1[i]='('+str(count)+')'+s1[i]
print('\n'.join(s1))

Linco · 发表于 2017-9-11 23:03:21

text = """FishC
FishC
FishC
FishC
Little turtle
Little turtle
Python
FishC"""
print(text.split('\n'))
out = {}
o = []
for line in text.split('\n'):
    prev = out.get(line, 0)
    if prev == 0 and len(out) != 0:
        k, v = out.popitem()
        for n in reversed(range(0, v)):
            o.append('(%s)%s' % (n, k))
    out[line] = out.get(line, 0) + 1
print('\n'.join(o))

liuwenqi · 发表于 2017-9-14 10:22:01

content ='''FishC
FishC
FishC
FishC
Little turtle
Little turtle
Python
FishC'''
content = content.split('\n')
for num,each in enumerate(content):
for i in range(num, len(content)):
      if i == False:
         print(0, each)
      elif each != content[i]:
         print(i-num-1, each)
         break

fangchuhao · 发表于 2017-9-14 19:00:12

问问

upc-xiaoxiao · 发表于 2017-9-14 22:37:49

学习一下

咖喱168 · 发表于 2017-9-15 09:28:58

不会

扫描仪 · 发表于 2017-10-4 07:48:45

不知道啊

timeislife · 发表于 2017-10-4 12:19:46

看看

shigure_takimi · 发表于 2017-12-4 13:15:45

a ='''FishC
FishC
FishC
FishC
Little turtle
Little turtle
Python
FishC'''

def func(string):
    b = string.split('\n')
    counts = [] # 存放每个字符串后面跟着的相同字符串的个数
    for i in range(len(b)):
        count_i = 0
        for j in range(i+1,len(b)):
            if b[i] == b[j]:
                count_i += 1
            else:
                break
        counts.append(count_i)
    for count_i, subString in zip(counts, b):
        print("({0}){1}".format(count_i,subString))
func(a)


##    >>> 
##    (3)FishC
##    (2)FishC
##    (1)FishC
##    (0)FishC
##    (1)Little turtle
##    (0)Little turtle
##    (0)Python
##    (0)FishC
##        
##    完美符合预期。

yjsx86 · 发表于 2018-1-31 02:28:47

s = '''FishC
FishC
FishC
FishC
Little turtle
Little turtle
Python
FishC'''
[print('(%d)%s' % (i,k)) for k,v in it.groupby(s.split('\n')) for i in range(len(list(v)))[::-1]]

新手潘包邮 · 发表于 2018-4-24 22:36:46

jerryxjr1220 发表于 2017-9-8 18:12

您好，大佬能不能分享下学习经验

新手潘包邮 · 发表于 2018-4-24 22:41:27

import itertools
def fun(string):
print(string)
string = string.split("\n")
string.reverse()
j = 0
string[0] = "(%s)"%j + string[0]
for i in range(1, len(string)):
      if string[i] == string[i-1][3:]:
         j += 1
         string[i] = "(%s)"%j + string[i]
      else:
         j = 0
         string[i] = "(%s)"%j + string[i]
print(string)
string.reverse()
a = itertools.groupby(string)
for i, j in a:
      print(i)
#print(a)
pass
fun("FishC\nFishC\nFishC\nLittle turtle\nLittle turtle\nFishC")

Geoffreylee · 发表于 2020-3-20 11:10:20

import itertools

def f_95(string: str):
    for key, group in itertools.groupby(string.split('\n')):
        lst = list(group)
        for index, value in enumerate(lst):
            print('({}) {}'.format(len(lst)-index-1, value))

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[技术交流] Python：每日一题 95（答题领鱼币）