论坛 › Python交流 › Python：每日一题 95（答题领鱼币）

guoqing3511 发表于 2017-9-10 16:47:15

print("1fishc|\n2fishc\n3fishc\n4fishc\n5little turtle\n")

5jj 发表于 2017-9-10 16:49:39

不知道

AKA2pac 发表于 2017-9-11 13:50:44

def addhead(list1):
    count = 0
    for i in range(0,len(list1)):
      for j in range(i + 1,len(list1)):
            if list1 == list1:
                count += 1
      print('(' + str(count) + ')' + list1)
      count = 0


list2 = ['FishC', 'FishC', 'FishC', 'FishC', 'Little turtle', 'Little turtle', 'Python', 'FishC']
addhead(list2)

741712547 发表于 2017-9-11 16:54:10

a = """FishC
FishC
FishC
FishC
Little turtle
Little turtle
Python
FishC"""
list1 = a.split('\n')
list3 = list1.copy()
list3.reverse()
list4 =
list5 = []

changdu = len(list3)
for index in range(1,changdu):
    if list3 == list3:
      list4.append(1)
      list4 = (list4+list4)
    else:
      list4.append(0)
for index in range(changdu):
    list5.append('('+str(list4)+')'+list3)
list5.reverse()
for char in list5:
    print(char)


思路是，用两个列表拼接。倒是实现了，但是有点笨办法。

dnwz 发表于 2017-9-11 18:57:04

strVal = """
    FishC
    FishC
    FishC
    FishC
    Little turtle
    Little turtle
    Python
    FishC
"""
newStrVal = strVal.split('\n')
strlist =
length = len(strlist)

for i in range(length):
&nbsp; &nbsp; j = i+1 if i+1<length else length
&nbsp; &nbsp; n = 0
&nbsp; &nbsp; for j in range(j,length):
&nbsp; &nbsp;&nbsp; &nbsp;&nbsp;&nbsp;if strlist == strlist:
&nbsp; &nbsp;&nbsp; &nbsp;&nbsp; &nbsp;&nbsp; &nbsp;n += 1
&nbsp; &nbsp;&nbsp; &nbsp;&nbsp;&nbsp;else:
&nbsp; &nbsp;&nbsp; &nbsp;&nbsp; &nbsp;&nbsp; &nbsp;break
&nbsp; &nbsp; print("(%d)%s" % (n,strlist))

dnwz 发表于 2017-9-11 18:57:43

{:10_251:}

lihuayuan 发表于 2017-9-11 19:39:29

不知道哦

根号三.5 发表于 2017-9-11 21:44:45

s1='''FishC
FishC
FishC
FishC
Little turtle
Little turtle
Python
FishC'''
s1=s1.split('\n')
num=len(s1)
for i in range(num):
    count=0
    for j in range(i+1,num):
      if s1==s1:
            count+=1
      else:
            break
    s1='('+str(count)+')'+s1
print('\n'.join(s1))

Linco 发表于 2017-9-11 23:03:21

text = """FishC
FishC
FishC
FishC
Little turtle
Little turtle
Python
FishC"""
print(text.split('\n'))
out = {}
o = []
for line in text.split('\n'):
    prev = out.get(line, 0)
    if prev == 0 and len(out) != 0:
      k, v = out.popitem()
      for n in reversed(range(0, v)):
            o.append('(%s)%s' % (n, k))
    out = out.get(line, 0) + 1
print('\n'.join(o))

liuwenqi 发表于 2017-9-14 10:22:01

content ='''FishC
FishC
FishC
FishC
Little turtle
Little turtle
Python
FishC'''
content = content.split('\n')
for num,each in enumerate(content):
    for i in range(num, len(content)):
      if i == False:
            print(0, each)
      elif each != content:
            print(i-num-1, each)
            break
   

fangchuhao 发表于 2017-9-14 19:00:12

问问

upc-xiaoxiao 发表于 2017-9-14 22:37:49

学习一下

咖喱168 发表于 2017-9-15 09:28:58

不会

扫描仪 发表于 2017-10-4 07:48:45

不知道啊

timeislife 发表于 2017-10-4 12:19:46

看看

shigure_takimi 发表于 2017-12-4 13:15:45

a ='''FishC
FishC
FishC
FishC
Little turtle
Little turtle
Python
FishC'''

def func(string):
    b = string.split('\n')
    counts = [] # 存放每个字符串后面跟着的相同字符串的个数
    for i in range(len(b)):
      count_i = 0
      for j in range(i+1,len(b)):
            if b == b:
                count_i += 1
            else:
                break
      counts.append(count_i)
    for count_i, subString in zip(counts, b):
      print("({0}){1}".format(count_i,subString))
func(a)


##    >>>
##    (3)FishC
##    (2)FishC
##    (1)FishC
##    (0)FishC
##    (1)Little turtle
##    (0)Little turtle
##    (0)Python
##    (0)FishC
##      
##    完美符合预期。

yjsx86 发表于 2018-1-31 02:28:47

s = '''FishC
FishC
FishC
FishC
Little turtle
Little turtle
Python
FishC'''
]

新手潘包邮 发表于 2018-4-24 22:36:46

jerryxjr1220 发表于 2017-9-8 18:12


您好，大佬能不能分享下学习经验

新手潘包邮 发表于 2018-4-24 22:41:27

import itertools
def fun(string):
    print(string)
    string = string.split("\n")
    string.reverse()
    j = 0
    string = "(%s)"%j + string
    for i in range(1, len(string)):
      if string == string:
            j += 1
            string = "(%s)"%j + string
      else:
            j = 0
            string = "(%s)"%j + string
    print(string)
    string.reverse()
    a = itertools.groupby(string)
    for i, j in a:
      print(i)
    #print(a)
    pass
fun("FishC\nFishC\nFishC\nLittle turtle\nLittle turtle\nFishC")

Geoffreylee 发表于 2020-3-20 11:10:20

import itertools

def f_95(string: str):
    for key, group in itertools.groupby(string.split('\n')):
      lst = list(group)
      for index, value in enumerate(lst):
            print('({}) {}'.format(len(lst)-index-1, value))

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