求解决问题~

凌九霄

1. a = [ 1, 2, 3, 4, 5, 6 ]
   
2. 
   
3. a.insert(0, a.pop())
   
4. b = a[ : ]
   
5. b.insert(0, b.pop())
   
6. c = b[ : ]
   
7. c.insert(0, c.pop())
   
8. d = c[ : ]
   
9. d.insert(0, d.pop())
   
10. e = d[ : ]
    
11. e.insert(0, e.pop())
    
12. f = e[ : ]
    
13. f.insert(0, f.pop())
    
14. 
    
15. print(a)
    
16. print(b)
    
17. print(c)
    
18. print(d)
    
19. print(e)
    
20. print(f)
    

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这个更灵活点，能处理任意长度的

1. def larray(lst, result=[ ]):
   
2.     i = len(result)
   
3.     i += 1
   
4.     if i <= len(lst):
   
5.         x = lst[ : ]
   
6.         x.insert(0, x.pop())
   
7.         result.append(x)
   
8.         larray(x)
   
9.     return result

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1. print(larray([x for x in range(1,7)]))
   
2. [[6, 1, 2, 3, 4, 5], [5, 6, 1, 2, 3, 4], [4, 5, 6, 1, 2, 3], [3, 4, 5, 6, 1, 2], [2, 3, 4, 5, 6, 1], [1, 2, 3, 4, 5, 6]]
   
3. 
   
4. print(larray([x for x in range(1,10)]))
   
5. [[9, 1, 2, 3, 4, 5, 6, 7, 8], [8, 9, 1, 2, 3, 4, 5, 6, 7], [7, 8, 9, 1, 2, 3, 4, 5, 6], [6, 7, 8, 9, 1, 2, 3, 4, 5], [5, 6, 7, 8, 9, 1, 2, 3, 4], [4, 5, 6, 7, 8, 9, 1, 2, 3], [3, 4, 5, 6, 7, 8, 9, 1, 2], [2, 3, 4, 5, 6, 7, 8, 9, 1], [1, 2, 3, 4, 5, 6, 7, 8, 9]]

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