本帖最后由 凌九霄 于 2018-8-26 12:11 编辑 a = [ 1, 2, 3, 4, 5, 6 ]
a.insert(0, a.pop())
b = a[ : ]
b.insert(0, b.pop())
c = b[ : ]
c.insert(0, c.pop())
d = c[ : ]
d.insert(0, d.pop())
e = d[ : ]
e.insert(0, e.pop())
f = e[ : ]
f.insert(0, f.pop())
print(a)
print(b)
print(c)
print(d)
print(e)
print(f)
这个更灵活点,能处理任意长度的def larray(lst, result=[ ]):
i = len(result)
i += 1
if i <= len(lst):
x = lst[ : ]
x.insert(0, x.pop())
result.append(x)
larray(x)
return result
print(larray([x for x in range(1,7)]))
[[6, 1, 2, 3, 4, 5], [5, 6, 1, 2, 3, 4], [4, 5, 6, 1, 2, 3], [3, 4, 5, 6, 1, 2], [2, 3, 4, 5, 6, 1], [1, 2, 3, 4, 5, 6]]
print(larray([x for x in range(1,10)]))
[[9, 1, 2, 3, 4, 5, 6, 7, 8], [8, 9, 1, 2, 3, 4, 5, 6, 7], [7, 8, 9, 1, 2, 3, 4, 5, 6], [6, 7, 8, 9, 1, 2, 3, 4, 5], [5, 6, 7, 8, 9, 1, 2, 3, 4], [4, 5, 6, 7, 8, 9, 1, 2, 3], [3, 4, 5, 6, 7, 8, 9, 1, 2], [2, 3, 4, 5, 6, 7, 8, 9, 1], [1, 2, 3, 4, 5, 6, 7, 8, 9]]
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