求解决问题~

xiabinbin

列表的方法：
生成以下列表：
a = [1,2,3,4,5,6]
b = [1,2,3,4,5,6]
c = [1,2,3,4,5,6]
d = [1,2,3,4,5,6]
e = [1,2,3,4,5,6]
f =  [1,2,3,4,5,6]

要生成的列表得到下面的结果：
a = [1,2,3,4,5,6]
b = [2,3,4,5,6,1]
c = [3,4,5,6,1,2]
d = [4,5,6,1,2,3]
e = [5,6,1,2,3,4]
f = [6,1,2,3,4,5]
目的：任何一个列表中的数字，横竖都不能有和它相同的数。

numpy.array的方法：
numpy.array([[1,2,3,4,5,6],[1,2,3,4,5,6],[1,2,3,4,5,6],[1,2,3,4,5,6],[1,2,3,4,5,6],[1,2,3,4,5,6]])
举例，要的结果是：
numpy.array([[1,2,3,4,5,6],[2,3,4,5,6,1],[3,4,5,6,1,2],[4,5,6,1,2,3],[5,6,1,2,3,4],[6,1,2,3,4,5]])
只要任何一个位置的数，横向和纵向都没有和它重复的就可以了。

要编程过程，重新生成结果也行，用已经生成的列表或者array排序得到也行。

claws0n

1. import numpy as np
   
2. 
   
3. a = np.array([1,2,3,4,5,6])
   
4. b = a[:]
   
5. c = a[:]
   
6. d = a[:]
   
7. e = a[:]
   
8. f = a[:]
   
9. g = np.array([a,b,c,d,e,f])
   
10. L = len(g[0])
    
11. for i in range(1,len(g)):
    
12.     g[i][0:L-1] = g[i-1][1:L]
    
13.     g[i][-1] = g[i-1][0]
    
14. print(g)

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1. [[1 2 3 4 5 6]
   
2. [2 3 4 5 6 1]
   
3. [3 4 5 6 1 2]
   
4. [4 5 6 1 2 3]
   
5. [5 6 1 2 3 4]
   
6. [6 1 2 3 4 5]]

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1. a = [1,2,3,4,5,6]
   
2. b = a[:]
   
3. c = a[:]
   
4. d = a[:]
   
5. e = a[:]
   
6. f = a[:]
   
7. g = [a,b,c,d,e,f]
   
8. L = len(g[0])
   
9. for i in range(1,len(g)):
   
10.     g[i][0:L-1] = g[i-1][1:L]
    
11.     g[i][-1] = g[i-1][0]
    
12. print(g)

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1. [[1, 2, 3, 4, 5, 6], [2, 3, 4, 5, 6, 1], [3, 4, 5, 6, 1, 2], [4, 5, 6, 1, 2, 3], [5, 6, 1, 2, 3, 4], [6, 1, 2, 3, 4, 5]]

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凌九霄

1. a = [ 1, 2, 3, 4, 5, 6 ]
   
2. 
   
3. a.insert(0, a.pop())
   
4. b = a[ : ]
   
5. b.insert(0, b.pop())
   
6. c = b[ : ]
   
7. c.insert(0, c.pop())
   
8. d = c[ : ]
   
9. d.insert(0, d.pop())
   
10. e = d[ : ]
    
11. e.insert(0, e.pop())
    
12. f = e[ : ]
    
13. f.insert(0, f.pop())
    
14. 
    
15. print(a)
    
16. print(b)
    
17. print(c)
    
18. print(d)
    
19. print(e)
    
20. print(f)
    

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这个更灵活点，能处理任意长度的

1. def larray(lst, result=[ ]):
   
2.     i = len(result)
   
3.     i += 1
   
4.     if i <= len(lst):
   
5.         x = lst[ : ]
   
6.         x.insert(0, x.pop())
   
7.         result.append(x)
   
8.         larray(x)
   
9.     return result

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1. print(larray([x for x in range(1,7)]))
   
2. [[6, 1, 2, 3, 4, 5], [5, 6, 1, 2, 3, 4], [4, 5, 6, 1, 2, 3], [3, 4, 5, 6, 1, 2], [2, 3, 4, 5, 6, 1], [1, 2, 3, 4, 5, 6]]
   
3. 
   
4. print(larray([x for x in range(1,10)]))
   
5. [[9, 1, 2, 3, 4, 5, 6, 7, 8], [8, 9, 1, 2, 3, 4, 5, 6, 7], [7, 8, 9, 1, 2, 3, 4, 5, 6], [6, 7, 8, 9, 1, 2, 3, 4, 5], [5, 6, 7, 8, 9, 1, 2, 3, 4], [4, 5, 6, 7, 8, 9, 1, 2, 3], [3, 4, 5, 6, 7, 8, 9, 1, 2], [2, 3, 4, 5, 6, 7, 8, 9, 1], [1, 2, 3, 4, 5, 6, 7, 8, 9]]

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