[已解决]Python：每日一题 260

panheng

1. def answer(lst):
   
2.     res = list(filter(lambda x: lst.count(x) > len(lst) / 2, set(lst)))
   
3.     if len(res) != 0:
   
4.         return res[0]
   
5.     else:
   
6.         return None

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