[已解决]什么是图片头，如何查看某张图片的图片头，如何删除图片头？

xhmjoy · 发表于 2020-1-4 11:18:53

什么是图片头，如何查看某张图片的图片头，如何删除图片头？谢谢！
图片头.PNG

最佳答案

XiaoPaiShen

2020-1-4 11:18:54

import base64
import re
import uuid
def decode_image(src):
result = re.search("data:image/(?P<ext>.*?);base64,(?P<data>.*)", src, re.DOTALL)
if result:
ext = result.groupdict().get("ext")
data = result.groupdict().get("data")
else:
raise Exception("Do not parse!")
img = base64.urlsafe_b64decode(data)
filename = "{}.{}".format(uuid.uuid4(), ext)
with open(filename, "wb") as f:
f.write(img)
return filename
def encode_image(filename):
ext = filename.split(".")[-1]
with open(filename, "rb") as f:
img = f.read()
data = base64.b64encode(img).decode()
src = "data:image/{ext};base64,{data}".format(ext=ext, data=data)
return src
if __name__ == '__main__':
print(encode_image("test.jpg"))
# src = "data:image/jpg;base64,/9j/4SCnRXhpZgA...="
# print(decode_image(src))

复制代码

XiaoPaiShen · 发表于 2020-1-4 11:18:54

import base64
import re
import uuid
def decode_image(src):
result = re.search("data:image/(?P<ext>.*?);base64,(?P<data>.*)", src, re.DOTALL)
if result:
ext = result.groupdict().get("ext")
data = result.groupdict().get("data")
else:
raise Exception("Do not parse!")
img = base64.urlsafe_b64decode(data)
filename = "{}.{}".format(uuid.uuid4(), ext)
with open(filename, "wb") as f:
f.write(img)
return filename
def encode_image(filename):
ext = filename.split(".")[-1]
with open(filename, "rb") as f:
img = f.read()
data = base64.b64encode(img).decode()
src = "data:image/{ext};base64,{data}".format(ext=ext, data=data)
return src
if __name__ == '__main__':
print(encode_image("test.jpg"))
# src = "data:image/jpg;base64,/9j/4SCnRXhpZgA...="
# print(decode_image(src))

复制代码

xhmjoy · 发表于 2020-1-6 11:00:20

xhmjoy · 发表于 2020-1-6 11:01:46

搜索关键字“PNG文件格式详解”、“JPG文件编解码详解”

账号		自动登录	找回密码
密码			立即注册