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Find the kth largest element in an unsorted array. Note that it is the kth largest element in the sorted order, not the kth distinct element.
Example 1:
Input: [3,2,1,5,6,4] and k = 2
Output: 5
Example 2:
Input: [3,2,3,1,2,4,5,5,6] and k = 4
Output: 4
Note:
You may assume k is always valid, 1 ≤ k ≤ array's length.
class Solution {
public int findKthLargest(int[] nums, int k) {
int max = Integer.MIN_VALUE;
int min = Integer.MAX_VALUE;
for(int i :nums){
if(i > max) max = i;
if(i < min) min = i;
}
int[] arr = new int[max - min +1];
for(int i = 0 ; i< nums.length; i++){
arr[nums[i] - min]++;
}
for(int i = arr.length-1; i>-1; i--){
if(arr[i] != 0) {
k = k - arr[i];
if(k <= 0) return i +min;
}
if(k == 0) return i+min;
}
return -1;
}
}
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