|
马上注册,结交更多好友,享用更多功能^_^
您需要 登录 才可以下载或查看,没有账号?立即注册
x
- Find the kth largest element in an unsorted array. Note that it is the kth largest element in the sorted order, not the kth distinct element.
- Example 1:
- Input: [3,2,1,5,6,4] and k = 2
- Output: 5
- Example 2:
- Input: [3,2,3,1,2,4,5,5,6] and k = 4
- Output: 4
- Note:
- You may assume k is always valid, 1 ≤ k ≤ array's length.
复制代码
- class Solution {
- public int findKthLargest(int[] nums, int k) {
- int max = Integer.MIN_VALUE;
- int min = Integer.MAX_VALUE;
-
- for(int i :nums){
- if(i > max) max = i;
- if(i < min) min = i;
- }
- int[] arr = new int[max - min +1];
-
- for(int i = 0 ; i< nums.length; i++){
- arr[nums[i] - min]++;
- }
- for(int i = arr.length-1; i>-1; i--){
-
- if(arr[i] != 0) {
-
- k = k - arr[i];
-
- if(k <= 0) return i +min;
- }
- if(k == 0) return i+min;
- }
-
- return -1;
- }
- }
复制代码 |
|