鱼C论坛

 找回密码
 立即注册
查看: 2467|回复: 0

[学习笔记] Leetcode 300. Longest Increasing Subsequence

[复制链接]
发表于 2020-8-4 00:52:25 | 显示全部楼层 |阅读模式

马上注册,结交更多好友,享用更多功能^_^

您需要 登录 才可以下载或查看,没有账号?立即注册

x
Given an unsorted array of integers, find the length of longest increasing subsequence.

Example:

Input: [10,9,2,5,3,7,101,18]
Output: 4 
Explanation: The longest increasing subsequence is [2,3,7,101], therefore the length is 4. 
Note:

There may be more than one LIS combination, it is only necessary for you to return the length.
Your algorithm should run in O(n2) complexity.
Follow up: Could you improve it to O(n log n) time complexity?
class Solution:
    def lengthOfLIS(self, nums: List[int]) -> int:
        if nums == None or len(nums) == 0:
            return 0
        dp = [1 for _ in nums]
        res = 1
        for i in range(len(nums)):
            for j in range(i + 1, len(nums)):
                if nums[j] > nums[i]:
                    dp[j] = max(dp[j], dp[i] + 1)
                res = max(res, dp[j])
        return res

本帖被以下淘专辑推荐:

想知道小甲鱼最近在做啥?请访问 -> ilovefishc.com
回复

使用道具 举报

您需要登录后才可以回帖 登录 | 立即注册

本版积分规则

小黑屋|手机版|Archiver|鱼C工作室 ( 粤ICP备18085999号-1 | 粤公网安备 44051102000585号)

GMT+8, 2024-10-2 19:35

Powered by Discuz! X3.4

© 2001-2023 Discuz! Team.

快速回复 返回顶部 返回列表