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Given an unsorted array of integers, find the length of longest increasing subsequence.
Example:
Input: [10,9,2,5,3,7,101,18]
Output: 4
Explanation: The longest increasing subsequence is [2,3,7,101], therefore the length is 4.
Note:
There may be more than one LIS combination, it is only necessary for you to return the length.
Your algorithm should run in O(n2) complexity.
Follow up: Could you improve it to O(n log n) time complexity?
class Solution:
def lengthOfLIS(self, nums: List[int]) -> int:
if nums == None or len(nums) == 0:
return 0
dp = [1 for _ in nums]
res = 1
for i in range(len(nums)):
for j in range(i + 1, len(nums)):
if nums[j] > nums[i]:
dp[j] = max(dp[j], dp[i] + 1)
res = max(res, dp[j])
return res
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