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[学习笔记] Leetcode 300. Longest Increasing Subsequence

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发表于 2020-8-4 00:52:25 | 显示全部楼层 |阅读模式

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  1. Given an unsorted array of integers, find the length of longest increasing subsequence.

  2. Example:

  3. Input: [10,9,2,5,3,7,101,18]
  4. Output: 4
  5. Explanation: The longest increasing subsequence is [2,3,7,101], therefore the length is 4.
  6. Note:

  7. There may be more than one LIS combination, it is only necessary for you to return the length.
  8. Your algorithm should run in O(n2) complexity.
  9. Follow up: Could you improve it to O(n log n) time complexity?
复制代码

  1. class Solution:
  2.     def lengthOfLIS(self, nums: List[int]) -> int:
  3.         if nums == None or len(nums) == 0:
  4.             return 0
  5.         dp = [1 for _ in nums]
  6.         res = 1
  7.         for i in range(len(nums)):
  8.             for j in range(i + 1, len(nums)):
  9.                 if nums[j] > nums[i]:
  10.                     dp[j] = max(dp[j], dp[i] + 1)
  11.                 res = max(res, dp[j])
  12.         return res
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