[已解决]求助 怎么改 谢谢！

MIQIWEI

get_pair_of_largest_numbers（numbers），该函数将数字列表作为参数，并返回具有最大和的相邻数字对作为元组。您可以假定列表不为空（至少两个或更多元素），并且每个元素都是有效数字。

def get_pair_of_largest_numbers(numbers):
    result = [numbers[index] + numbers[index+1] for index in range(len(numbers)-1)]
    max_value = result[0]
    for index in range(len(result)):
        if result[index] > max_value:
            max_value = result[index]
    return max_value

Test        Result
print(get_pair_of_largest_numbers([10.5, -3, -1, 11]))
(-1, 11)
print(get_pair_of_largest_numbers([ 10, 20, 3, 31, 8, 42]))
(8, 42)
print(get_pair_of_largest_numbers([ 10.5, -3]))
(10.5, -3)

最佳答案

月排行榜 / 总排行榜

Twilight6

2020-8-16 17:28:29

def get_pair_of_largest_numbers(numbers):
    result = [numbers[index] + numbers[index+1] for index in range(len(numbers)-1)]
    max_value = result.index(max(result))
    return tuple(numbers[max_value:max_value+2])

print(get_pair_of_largest_numbers([10.5, -3, -1, 11]))
print(get_pair_of_largest_numbers([ 10, 20, 3, 31, 8, 42]))
print(get_pair_of_largest_numbers([ 10.5, -3]))

跳转到最佳答案楼层

Twilight6

def get_pair_of_largest_numbers(numbers):
    result = [numbers[index] + numbers[index+1] for index in range(len(numbers)-1)]
    max_value = result.index(max(result))
    return tuple(numbers[max_value:max_value+2])

print(get_pair_of_largest_numbers([10.5, -3, -1, 11]))
print(get_pair_of_largest_numbers([ 10, 20, 3, 31, 8, 42]))
print(get_pair_of_largest_numbers([ 10.5, -3]))