请用一行代码实现按得分排序

GeaAZous

1

fanlinhui

1

丢的FC

1

mengtaiqi

5

misajdisajdio

x = { k: [i for i,j in sorted(v.items(), key=lambda x:x[1], reverse=True)]   for k,v in members.items()  }

苗生海海

x = {k: tuple(item[0] for item in sorted(v.items(), key=lambda x:x[1], reverse=True)) for k, v in members.items() }
x

stumblemodel

把每一项都和前面一项比较,交换位置

NanShan_bob

for x in members.keys():
    s =[s[0]  for s in sorted(list(members[x].items()), key =lambda a : a[1], reverse=True)]
    print(x,s)

15135710508

x = {k:tuple([each[0] for each in sorted(list(members[k].items()),key = lambda x:x[1],reverse = True)]) for k in members.keys()}

猪猪女孩_Lei

1

zjkjsdvkj

就是好奇一下lambda的应用

jjkang

1. x = {team:tuple(sorted(members[team], key=members[team].get, reverse=True)) for team in members}
   

复制代码

洛羽qaq

5

player-none

1. x = {k: (sorted(???这段不清楚???)) for k, v in members.items()}

复制代码

落霞云归晚mio

nbmn

Xptdad

x = {team:tuple(sorted(members_dict, key=lambda k: members_dict[k])) for team, members_dict in members.items() }

brav

1

日立sunrise

1

愚人的国度

LRX1114

sort