请用一行代码实现按得分排序

冬雪雪冬

写的比较乱，看看小甲鱼的答案。

1. x = {keys: tuple(sorted(values, key = lambda x: -values[x])) for keys, values in members.items()}

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Mikusaikou39

print(sorted(list(map(int,input("请输入得分：").split()))))

zhyuchao123

x = {team:[name for name,_ in sorted([[member,members[team][member]] for member in members[team]], key= lambda name_score_pair:name_score_pair[1], reverse=True)] for team in members}

Royalvice

x = {i:tuple([j[0] for j in sorted(members[i].items(), key=lambda item:item[1], reverse=True)]) for i in members}

gyh666

members.sort(reverse=True)

潘达张

x = dict((k,tuple( m[0] for m in sorted(v.items(),key= lambda x: x[1],reverse=True))) for k,v in members.items())

juncao50

x={i:tuple(sorted(list(v),key=lambda j:v[j],reverse=True)) for i,v in members.items()}

quechua128

x = ｛key:［st[0] for st in sorted(val.items(), key = lambda kv:(kv[1], kv[0]),  reverse = True)］for key,val in members()｝

DetConan

x = {k:{a:b for a,b in sorted(v.items(),key=lambda m:-m[1])} for k,v in members.items()}

258947758

x=dict([i,tuple(map(lambda k:dict(zip(j.values(),j.keys())).get(k),sorted(j.values())))]for i,j in members.items())
ˉˉˉˉˉˉˉˉˉˉˉˉˉˉˉˉ检查了下发现排序没倒序，作如下更新ˉˉˉˉˉˉˉˉˉˉˉ
x=dict([i,tuple(map(lambda k:dict(zip(j.values(),j.keys())).get(k),sorted(j.values(),reverse=True)))]for i,j in members.items())

Mikusaikou39

print(sorted(list(map(float,input().split()))))

Pliosauroidea

1. x = {k: tuple(item[0] for item in sorted(v.items(), key=lambda z: z[1],reverse=True)) for k, v in members.items()}

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Richard_Chiang

x = dict((team, tuple(m[0] for m in sorted(members[team].items(), key=lambda i: i[1], reverse=True))) for team in members)

sryml

1. x = {k: tuple(sorted(v, key=v.get, reverse=True)) for k, v in members.items()}

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1596429368

members=sorted(d.items(),key=lambda x:x[1],reverse=True)

comprehensive

x = dict(zip(members, [tuple(sorted(team[1], key=lambda name: -team[1][name])) for team in members.items()]))

持枪揽星河

for value in members.values():
    x = sorted(value.items(), key = lambda a:a[1], reverse = True)
    print(x)

HF_Z

x = {k : tuple(map(lambda item: item[0], sorted(v.items(), reverse=True, key=lambda item: item[1]))) for k, v in members.items()}

tbyouth

1. x = {k : tuple(sorted(v.keys(), key = lambda name : v[name])) for k,v in members.items()}

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