0基础第20讲课后题，感觉答案不对吧？

fang232629

这是题目：
1. 请用已学过的知识编写程序，找出小甲鱼藏在下边这个长字符串中的密码，密码的埋藏点符合以下规律：
    a) 每位密码为单个小写字母Powered by bbs.fishc.com
    b) 每位密码的左右两边均有且只有三个大写字母
然后这是标准答案：

str1 = '''ABSaDKSbRIHcRHGcdDIF'''     #str1的字符串内容在下面，替换一下就好

countA = 0  # 统计前边的大写字母
countB = 0  # 统计小写字母
countC = 0  # 统计后边的大写字母
length = len(str1)

for i in range(length):
    if str1[i] == '\n':
        continue

    """
    |如果str1[i]是大写字母：
    |-- 如果已经出现小写字母：
    |-- -- 统计后边的大写字母
    |-- 如果未出现小写字母：
    |-- -- 清空后边大写字母的统计
    |-- -- 统计前边的大写字母
    """
    if str1[i].isupper():
        if countB:
            countC += 1
        else:
            countC = 0
            countA += 1

    """
    |如果str1[i]是小写字母：
    |-- 如果小写字母前边不是三个大写字母（不符合条件）：
    |-- -- 清空所有记录，重新统计
    |-- 如果小写字母前边是三个大写字母（符合条件）：
    |-- -- 如果已经存在小写字母：
    |-- -- -- 清空所有记录，重新统计（出现两个小写字母）
    |-- -- 如果该小写字母是唯一的：
    |-- -- -- countB记录出现小写字母，准备开始统计countC
    """
    if str1[i].islower():
        if countA != 3:
            countA = 0
            countB = 0
            countC = 0
        else: 
            if countB:
                countA = 0
                countB = 0
                countC = 0
            else:
                countB = 1
                countC = 0
                target = i

    """
    |如果前边和后边都是三个大写字母：
    |-- 如果后边第四个字母也是大写字母（不符合条件）：
    |-- -- 清空记录B和C，重新统计
    |-- 如果后边仅有三个大写字母（符合所有条件）：
    |-- -- 打印结果，并清空所有记录，进入下一轮统计
    """
    if countA == 3 and countC == 3:
        if i+1 != length and str1[i+1].isupper():
            countB = 0
            countC = 0
        else:
            print(str1[target], end='')
            countA = 3
            countB = 0
            countC = 0

然后这是我的解题：

str1 = '''ABSaDKSbRIHcRHGcdDIF'''   #str1的字符串内容在下面，替换一下就好pwd = []
count = 3
for each in str1[3:-4]:

    if each.islower():
        if not (str1[count-3].islower() and str1[count-2].islower() and str1[count-1].islower() and str1[count+1].islower() and str1[count+2].islower() and str1[count+3].islower()):
            pwd.append(each)
        else:
            continue
    else:
        continue
    count += 1

for i in pwd:
    print(i, end='')

str1是下面的内容

ACFlCTLIQlAIVMTqHFkswqbDDHtpgcWaXSSglUYKE
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qKWGc

我的运行结果：

llqkswqbtpgcagllqsyazrbkrgtlqhpwquqpslfllwptqjruzwvbxoritpgadkzvnvmlsmqydqyboenkuiiikspgsmhnppfmkpjjceavgsvkgtzleephrpxqinuwursznpxhstpdzqenttlibhbpwsthiwzambmqmwofyxmczjcffccbzhudsaspjrvanrqanmbobftkjjhleauuiaqisgm

我感觉挺符合题目要求的啊。难道我理解错了？