Python：每日一题 142

kinkon

1. def fun142(start, stop):
   
2.     sta = start.split(':')
   
3.     A = int(sta[0]) * 3600 + int(sta[1]) * 60 + int(sta[2])
   
4.     end = stop.split(':')
   
5.     B = int(end[0]) * 3600 + int(end[1]) * 60 + int(end[2])
   
6.     return '时间差为：' + str(B - A if B > A else 86400 + B - A) + 's'
   
7.    
   
8.         
   
9. start = '17:55:31'
   
10. stop = '24:21:57'
    
11. 
    
12. print(fun142(start, stop))

复制代码