爬取百度翻译遇到的问题

Hello-Python3

import urllib.request
import urllib.parse
url='http://fanyi.baidu.com/langdetect'
head={}
head['user-agent']='Mozilla/5.0 (Windows NT 5.1) AppleWebKit/537.36 (KHTML, like Gecko) Chrome/49.0.2623.112 Safari/537.36'
data={}
data['query']='你好'
data=urllib.parse.urlencode(data).encode('utf-8')
rsp=urllib.request.urlopen(url,data,head)
html=rsp.read().decode('utf-8')
print(html)

运行上述代码，系统抛出a float is required错误，不知道是什么情况，希望有人能给我解答一下，

ba21

1. import urllib.request
   
2. import urllib.parse
   
3. url='http://fanyi.baidu.com/langdetect'
   
4. head={}
   
5. head['user-agent']='Mozilla/5.0 (Windows NT 5.1) AppleWebKit/537.36 (KHTML, like Gecko) Chrome/49.0.2623.112 Safari/537.36'
   
6. data={}
   
7. data['query']='你好'
   
8. data=urllib.parse.urlencode(data).encode('utf-8')
   
9. 
   
10. req=urllib.request.Request(url,data,head)
    
11. rsp=urllib.request.urlopen(req)
    
12. 
    
13. html=rsp.read().decode('utf-8')
    
14. print(html)
    

复制代码

sky

用requests模块 urllib不会
urlopen接受不了headers参数
具体不清楚 太乱了 没研究
urllib应该是先构建一个request对象 然后再调用访问的

1. import urllib.request
   
2. import urllib.parse
   
3. url='http://fanyi.baidu.com/langdetect'
   
4. head={}
   
5. head['user-agent']='Mozilla/5.0 (Windows NT 5.1) AppleWebKit/537.36 (KHTML, like Gecko) Chrome/49.0.2623.112 Safari/537.36'
   
6. data={}
   
7. data['query'] = '你好'
   
8. data = urllib.parse.urlencode(data)
   
9. data = data.encode('ascii')
   
10. res = urllib.request.urlopen(url, data)
    
11. html = res.read().decode('utf-8')
    
12. print(html)
    

复制代码

所以说很乱