[已解决]帮忙看下这个代码，如何让”count-1等于2“生效，谢谢

xue11

count = 3
a = "*"
password = "FishC.com"
each = input("请输入密码：")
while True:
    if a in each:
        each = input("密码中不能含有*号！您还有3次机会！请输入密码：")
        continue
    if password == each:
        break
    elif password != each:
        each = input("密码输入错误！您还有count-1次机会！请输入密码：")
        count = count-1
print("密码正确，进入程序.....")

最佳答案

月排行榜 / 总排行榜

ba21

2018-2-3 20:16:36

count = 3
a = "*"
password = "FishC.com"
each = input("请输入密码：")
while True:
    if a in each:
        each = input("密码中不能含有*号！您还有3次机会！请输入密码：")
        continue
    if password == each:
        print("密码正确，进入程序.....")
        break
    elif count == 0:
        print("3次错误，退出程序.....")
        break
    else:
        each = input("密码输入错误！您还有 %d 次机会！请输入密码：" %  count )
        count = count-1

跳转到最佳答案楼层

ba21

count = 3
a = "*"
password = "FishC.com"
each = input("请输入密码：")
while True:
    if a in each:
        each = input("密码中不能含有*号！您还有3次机会！请输入密码：")
        continue
    if password == each:
        print("密码正确，进入程序.....")
        break
    elif count == 0:
        print("3次错误，退出程序.....")
        break
    else:
        each = input("密码输入错误！您还有 %d 次机会！请输入密码：" %  count )
        count = count-1

BngThea

用格式化输入输出方式
each = input("密码输入错误！您还有 %d 次机会！请输入密码：" % ( count -1))