Python：每日一题 161

冬雪雪冬 · 发表于 2018-3-9 21:05:41

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本帖最后由冬雪雪冬于 2018-3-12 21:19 编辑

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题目：
实现打印字母三角形，如:
fun(1)输出:
A
fun(2)输出
A
ABA
fun(3)输出:
A
ABA
ABCBA
fun(28)最底层应为:
ABCDEFGHIJKLMNOPQRSTUVWXYZABAZYXWVUTSRQPONMLKJIHGFEDCBA
即当达到字母Z以后再从A开始。

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Chase_Kas · 发表于 2018-3-9 21:49:40

本帖最后由 Chase_Kas 于 2018-3-10 11:52 编辑

def fun(n):
def alpha(m):
asc = 64
str1 = ''
for i in range(m+1):
if asc == 90:
asc = 64
asc += 1
str1 += chr(asc)
for i in range(m):
if asc == 65:
asc = 91
asc -= 1
str1 += chr(asc)
return str1
for i in range(n):
print(alpha(i).center(n*2 -1))
fun(30)

复制代码

仔细分析三角形后发现下一行仅仅是比上一行多了两个字符，重写了后效率高出了一大截

def fun(n):
asc, asc1 = 66, 65
str1 = 'A'
for i in range(n):
if i == 0:
print(str1.center(n*2 -1))
continue
str1 = str1[:i] + chr(asc) + chr(asc1) + str1[i:]
asc += 1
asc1 += 1
if asc > 90:
asc = 65
if asc1 > 90:
asc1 = 65
print(str1.center(n*2 - 1))
fun(135)

复制代码

t6am3 · 发表于 2018-3-9 22:19:07

本帖最后由 t6am3 于 2018-3-9 22:36 编辑

#第一种：
def triangle(n, N):
base = 65
print(' '*(N-n), end='');
stack = []
for i in range(n):
      t = base+(i%26)
      print('%c'% t, end='')
      if i != n-1:
         stack.append('%c'%t)
stack.reverse()
for eachletter in stack:
      print(eachletter, end='')
print('')

def fun(n):
for i in range(1, n+1):
      triangle(i, n)

#第二种好像简单一点点？……：
def triangle(n, N):
print(' '*(N-n), end='')
Stack = list((range(n)))
for i in Stack:
      print('%c'%(65+i%26), end='')
Stack.pop()
Stack.reverse()
for i in Stack:
      print('%c'%(65+i%26), end='')
print('')

def fun(n):
for i in range(1, n+1):
      triangle(i, n)

溯影 · 发表于 2018-3-9 23:05:55

def fun(number):
str1 = 'ABCDEFGHIJKLMNOPQRSTUVWXYZ'
for i in range(number):
for j in range(0,number-i-1):
print(' ',end = '')
for j in range(i+1):
print(str1[j%26],end = '')
for j in range(i):
print(str1[(i-j-1)%26],end = '')
print('')#换行
if __name__ == '__main__':
number = int(input('请输入数字:'))
fun(number)

复制代码

结果1：
请输入数字:3
A
ABA
ABCBA

***Repl Closed***
结果2：

请输入数字:26
A
ABA
ABCBA
ABCDCBA
ABCDEDCBA
ABCDEFEDCBA
ABCDEFGFEDCBA
ABCDEFGHGFEDCBA
ABCDEFGHIHGFEDCBA
ABCDEFGHIJIHGFEDCBA
ABCDEFGHIJKJIHGFEDCBA
ABCDEFGHIJKLKJIHGFEDCBA
ABCDEFGHIJKLMLKJIHGFEDCBA
ABCDEFGHIJKLMNMLKJIHGFEDCBA
ABCDEFGHIJKLMNONMLKJIHGFEDCBA
ABCDEFGHIJKLMNOPONMLKJIHGFEDCBA
ABCDEFGHIJKLMNOPQPONMLKJIHGFEDCBA
ABCDEFGHIJKLMNOPQRQPONMLKJIHGFEDCBA
ABCDEFGHIJKLMNOPQRSRQPONMLKJIHGFEDCBA
ABCDEFGHIJKLMNOPQRSTSRQPONMLKJIHGFEDCBA
ABCDEFGHIJKLMNOPQRSTUTSRQPONMLKJIHGFEDCBA
ABCDEFGHIJKLMNOPQRSTUVUTSRQPONMLKJIHGFEDCBA
ABCDEFGHIJKLMNOPQRSTUVWVUTSRQPONMLKJIHGFEDCBA
ABCDEFGHIJKLMNOPQRSTUVWXWVUTSRQPONMLKJIHGFEDCBA
ABCDEFGHIJKLMNOPQRSTUVWXYXWVUTSRQPONMLKJIHGFEDCBA
ABCDEFGHIJKLMNOPQRSTUVWXYZYXWVUTSRQPONMLKJIHGFEDCBA
***Repl Closed***

复制代码

结果3：
请输入数字:27
                        A
                     ABA
                     ABCBA
                     ABCDCBA
                  ABCDEDCBA
                  ABCDEFEDCBA
                  ABCDEFGFEDCBA
               ABCDEFGHGFEDCBA
               ABCDEFGHIHGFEDCBA
               ABCDEFGHIJIHGFEDCBA
            ABCDEFGHIJKJIHGFEDCBA
            ABCDEFGHIJKLKJIHGFEDCBA
            ABCDEFGHIJKLMLKJIHGFEDCBA
         ABCDEFGHIJKLMNMLKJIHGFEDCBA
         ABCDEFGHIJKLMNONMLKJIHGFEDCBA
         ABCDEFGHIJKLMNOPONMLKJIHGFEDCBA
      ABCDEFGHIJKLMNOPQPONMLKJIHGFEDCBA
      ABCDEFGHIJKLMNOPQRQPONMLKJIHGFEDCBA
      ABCDEFGHIJKLMNOPQRSRQPONMLKJIHGFEDCBA
   ABCDEFGHIJKLMNOPQRSTSRQPONMLKJIHGFEDCBA
   ABCDEFGHIJKLMNOPQRSTUTSRQPONMLKJIHGFEDCBA
   ABCDEFGHIJKLMNOPQRSTUVUTSRQPONMLKJIHGFEDCBA
ABCDEFGHIJKLMNOPQRSTUVWVUTSRQPONMLKJIHGFEDCBA
ABCDEFGHIJKLMNOPQRSTUVWXWVUTSRQPONMLKJIHGFEDCBA
  ABCDEFGHIJKLMNOPQRSTUVWXYXWVUTSRQPONMLKJIHGFEDCBA
ABCDEFGHIJKLMNOPQRSTUVWXYZYXWVUTSRQPONMLKJIHGFEDCBA
ABCDEFGHIJKLMNOPQRSTUVWXYZAZYXWVUTSRQPONMLKJIHGFEDCBA

***Repl Closed***
结果4：
请输入数字:28
                        A
                        ABA
                     ABCBA
                     ABCDCBA
                     ABCDEDCBA
                  ABCDEFEDCBA
                  ABCDEFGFEDCBA
                  ABCDEFGHGFEDCBA
               ABCDEFGHIHGFEDCBA
               ABCDEFGHIJIHGFEDCBA
               ABCDEFGHIJKJIHGFEDCBA
            ABCDEFGHIJKLKJIHGFEDCBA
            ABCDEFGHIJKLMLKJIHGFEDCBA
            ABCDEFGHIJKLMNMLKJIHGFEDCBA
         ABCDEFGHIJKLMNONMLKJIHGFEDCBA
         ABCDEFGHIJKLMNOPONMLKJIHGFEDCBA
         ABCDEFGHIJKLMNOPQPONMLKJIHGFEDCBA
      ABCDEFGHIJKLMNOPQRQPONMLKJIHGFEDCBA
      ABCDEFGHIJKLMNOPQRSRQPONMLKJIHGFEDCBA
      ABCDEFGHIJKLMNOPQRSTSRQPONMLKJIHGFEDCBA
   ABCDEFGHIJKLMNOPQRSTUTSRQPONMLKJIHGFEDCBA
   ABCDEFGHIJKLMNOPQRSTUVUTSRQPONMLKJIHGFEDCBA
   ABCDEFGHIJKLMNOPQRSTUVWVUTSRQPONMLKJIHGFEDCBA
ABCDEFGHIJKLMNOPQRSTUVWXWVUTSRQPONMLKJIHGFEDCBA
ABCDEFGHIJKLMNOPQRSTUVWXYXWVUTSRQPONMLKJIHGFEDCBA
  ABCDEFGHIJKLMNOPQRSTUVWXYZYXWVUTSRQPONMLKJIHGFEDCBA
ABCDEFGHIJKLMNOPQRSTUVWXYZAZYXWVUTSRQPONMLKJIHGFEDCBA
ABCDEFGHIJKLMNOPQRSTUVWXYZABAZYXWVUTSRQPONMLKJIHGFEDCBA

***Repl Closed***

溯影 · 发表于 2018-3-9 23:08:39

file:///C:/Users/pc/Desktop/QQ%E5%9B%BE%E7%89%8720180309230728.png

°蓝鲤歌蓝 · 发表于 2018-3-9 23:15:38

本帖最后由 °蓝鲤歌蓝于 2018-3-9 23:24 编辑

def fun(num):
eng = ''.join(chr(i) for i in range(65, 91))
if num > 26:
eng = eng*(num//26)
eng += eng[:num-26]
n = 1
while n <= num:
print(' ' * (num - n), end='')
result = eng[:int(n-0.5)+1] + eng[:int(n-0.5)][::-1]
print(result)
n += 1
fun(4)
fun(26)
fun(28)
fun(53)

复制代码

雪人爱晒大太阳 · 发表于 2018-3-9 23:19:27

本帖最后由雪人爱晒大太阳于 2018-3-9 23:21 编辑

想了好久。。。终于想到了。。

#Define the each_line_print function
def each_line_print(n,n_sum):
#list_alphabet = [chr(i).upper() for i in range(97,123)]
list_alphabet = ''.join([chr(i).upper() for i in range(97,123)])
recycle = n//26 #how many times will the n goes for the recycle of the alphabet
flag = n%26 #how will the n last on which alpha
r = recycle
f = flag
list_print = ' '*(n_sum-n)#identify the numbers of space each line '*'
while r > 0:
list_print += list_alphabet
r -= 1
list_print += list_alphabet[0:f]
list_print_reverse = list_print[::-1]
list_print += list_print_reverse[1:]
return list_print
def fun(n):
k = 0
while k < n:
print(each_line_print(k+1,n))
k += 1
在程序中是对称的，但是不知道为什么在这个帖子里面显示的会是这么不对称。。。
>>> fun(1)
A
>>> fun(2)
A
ABA
>>> fun(3)
A
ABA
ABCBA
>>> fun(4)
A
ABA
ABCBA
ABCDCBA
>>> fun(5)
A
ABA
ABCBA
ABCDCBA
ABCDEDCBA
>>> fun(28)
A
ABA
ABCBA
ABCDCBA
ABCDEDCBA
ABCDEFEDCBA
ABCDEFGFEDCBA
ABCDEFGHGFEDCBA
ABCDEFGHIHGFEDCBA
ABCDEFGHIJIHGFEDCBA
ABCDEFGHIJKJIHGFEDCBA
ABCDEFGHIJKLKJIHGFEDCBA
ABCDEFGHIJKLMLKJIHGFEDCBA
ABCDEFGHIJKLMNMLKJIHGFEDCBA
ABCDEFGHIJKLMNONMLKJIHGFEDCBA
ABCDEFGHIJKLMNOPONMLKJIHGFEDCBA
ABCDEFGHIJKLMNOPQPONMLKJIHGFEDCBA
ABCDEFGHIJKLMNOPQRQPONMLKJIHGFEDCBA
ABCDEFGHIJKLMNOPQRSRQPONMLKJIHGFEDCBA
ABCDEFGHIJKLMNOPQRSTSRQPONMLKJIHGFEDCBA
ABCDEFGHIJKLMNOPQRSTUTSRQPONMLKJIHGFEDCBA
ABCDEFGHIJKLMNOPQRSTUVUTSRQPONMLKJIHGFEDCBA
ABCDEFGHIJKLMNOPQRSTUVWVUTSRQPONMLKJIHGFEDCBA
ABCDEFGHIJKLMNOPQRSTUVWXWVUTSRQPONMLKJIHGFEDCBA
ABCDEFGHIJKLMNOPQRSTUVWXYXWVUTSRQPONMLKJIHGFEDCBA
ABCDEFGHIJKLMNOPQRSTUVWXYZYXWVUTSRQPONMLKJIHGFEDCBA
ABCDEFGHIJKLMNOPQRSTUVWXYZAZYXWVUTSRQPONMLKJIHGFEDCBA
ABCDEFGHIJKLMNOPQRSTUVWXYZABAZYXWVUTSRQPONMLKJIHGFEDCBA

复制代码

shigure_takimi · 发表于 2018-3-9 23:23:11

# 我的代码。
def f(n):
s = 'ABCDEFGHIJKLMNOPQRSTUVWXYZ'
width = 2 * n- 1
for i in range(n):
a = (i//26)*s+s[:i%26+1]
a = a + a[::-1][1:]
print(a.center(width))
f(3)
f(5)
f(28)

复制代码

晓屁屁 · 发表于 2018-3-9 23:29:27

def fun(num):
str1 = ''
count1 = 0
count2 = 0
for i in range(num):
      if i > 25:
         str1 += chr(65+count2)
         count2 += 1
      else:
         str1 += chr(65 + i)
      for x in range(len(str1)):
         str2 = reversed(str1)
         str3 = str1 + ''.join(list(str2))
         str3 = str3[:count1] + str3[count1 + 1:]
         print(' '*(num-(i-1))+str3)
         count1 += 1
         break
fun(28)

ouyunfu · 发表于 2018-3-9 23:38:11

A=[chr(i) for i in range(65,91)]
def fun1(x):
B=A[:x-1]
if x<=26:
      return A[:x]+B[::-1]
else:
      B=A[:x-1-26]
      return A+A[:x-26]+B[::-1]+A[::-1]

def fun(n):
m=1
while n:
      print(' '*n,end='')
      for i in fun1(m):
         print(i,end='')
      m=m+1
      n=n-1
      print('')

if __name__ == '__main__':
fun(eval(input('请输入阶数：')))

坑得飞起 · 发表于 2018-3-9 23:38:58

本帖最后由坑得飞起于 2018-3-9 23:44 编辑

n=int(input())
str1="ABCDEFGHIJKLMNOPQRSTUVWXYZ"
for i in range(1, n+1):
j = " " * ( n - i )
str2=''
#print(i)
while i>26 :
      str2+=str1
      i-=26
str2+=str1[0:i]
k=len(str2)
str3=''
for cc in range(0,k):
      str3+=str2[k-cc-1]
print(j+str2+str3[1:])

坑得飞起 · 发表于 2018-3-9 23:43:47

n=int(input())
str1="ABCDEFGHIJKLMNOPQRSTUVWXYZ"
for i in range(1, n+1):
j = " " * ( n - i )
str2=''
while i>26 :
      str2+=str1
      i-=26
str2+=str1[0:i]
k=len(str2)
str3=''
for cc in range(0,k):
      str3+=str2[k-cc-1]
print(j+str2+str3[1:])

被翻红浪 · 发表于 2018-3-10 00:50:36

def fun(n):
for i in range(1, n+1):
str1 = ''
for j in range(1, i+1):
if j <= 26:
str1 += chr(64 + j)
else:
char = j % 26
if char == 0:
str1 += 'Z'
else:
str1 += chr(64 + char)
print(' ' * (n - i) + str1 + str1[::-1][1:] + ' ' * (n - i))

复制代码

fc1735 · 发表于 2018-3-10 01:23:04

def fun(n):
if not isinstance(n,int) or n<1: return
begin=''
end=''
n-=1
for i in range(n+1):
c='%c' %((i)%26+65)
print(' '*(n-i),begin,c,end,sep='')
begin+=c
end=c+end

复制代码

125zl · 发表于 2018-3-10 02:40:44

def fun(n):
for i in range(n):
      if n <= 100:
         str_n = ''
         s = 0
         t = 0
         for j in range(2 * n + 1):
            if j >= n - i and j <= n:
                  if ord('A') + j - n + i - s > ord('Z'):
                     s += 26
                  if ord('A') + j - n + i - s < ord('A'):
                     s -= 26
                  str_n += chr(ord('A') + j - n + i - s)
            elif j > n and j <= n + i:
                  if ord('A') + i - j + n - t - s > ord('Z'):
                     t += 26
                  if ord('A') + i - j + n - t -s < ord('A'):
                     t -= 26
                  str_n += chr(ord('A') + i - j + n - s - t)
            else:
                  str_n += ' '
         print(str_n)
n = int(input('请输入一个正整数:'))
fun(n)

阿bang · 发表于 2018-3-10 04:07:43

def traigle(number):
lineChar = ['A','B','A']
lineString = ['A','ABA']
if number == 1:
print 'A'
return
elif number == 2:
for i in lineString:
print i.center(2 * number - 1)
return
for i in range(3,number + 1):
if lineChar[(len(lineChar) - 1) / 2] != 'Z':
lineChar.insert((len(lineChar) + 1) / 2,chr(ord(lineChar[(len(lineChar) + 1) / 2 - 1])))
lineChar.insert((len(lineChar) + 1) / 2,chr(ord(lineChar[(len(lineChar) + 1) / 2 - 1]) + 1))
else:
lineChar.insert((len(lineChar) + 1) / 2,'A')
lineChar.insert((len(lineChar) + 1) / 2 + 1,'Z')
a = ''
for i in lineChar:
a += i
lineString.append(a)
for i in lineString:
print i.center(2 * number - 1)
number = input('Please input a number:')
traigle(number)

复制代码

阿bang · 发表于 2018-3-10 05:07:00

重新用了最直白的方法：

def traigle(number):
for i in range(1,number+1):
line = ''
t = 0
for j in range(1,2 * i):
if j < (i + 1) :
line += chr(ord('A') + t)
else:
line += line[2 * i - 1 - j]
if chr(ord('A') + t) == 'Z':
t -= 26
t += 1
print line.center(2 * number - 1)
number = input('please input a number:')
traigle(number)

复制代码

solomonxian · 发表于 2018-3-10 08:24:58

本帖最后由 solomonxian 于 2018-3-10 08:30 编辑

用chr()函数找

def fun(n):
return '\n'.join("".join(chr((i - abs(j)-1) % 26 + 65)
for j in range(-i+1, i)).center(2*n-1)
for i in range(1, n+1))

复制代码

感觉可能直接索引会比较快

def fun2(n):
string = "ABCDEFGHIJKLMNOPQRSTUVWXYZ"
result = []
for i in range(n):
temp = ''
num = i
while len(temp) <= i:
temp += string[:num+1]
num -= 26
result.append((temp[:] + temp[-2::-1]).center(2*n - 1))
return "\n".join(result)

复制代码

LargeCat · 发表于 2018-3-10 09:47:34

本帖最后由 LargeCat 于 2018-3-10 09:49 编辑

def Convert(n):
C=lambda x: chr(x%26+64) if x%26 else 'Z'
string=''
string1=''
for i1 in range(1, n+1):
string=string+C(i1)
for i2 in string[::-1][1:]:
string1=string1+i2
return string+string1
def Run(n):
for i in range(1, n+1):
print(Convert(i))
Run(5) #以输入5进行测试

复制代码

结果：

A
ABA
ABCBA
ABCDCBA
ABCDEDCBA

复制代码

newbieofnewbie · 发表于 2018-3-10 10:01:42

number = input()
temp = 'A'
i = 0
while i < int(number):
j = int(number)-i
#print(ord(temp)+1)
d=0
while d < j-1:
      print(" ",end='')
      d = d + 1
d=0
while d <= i:
      if ord(temp)+ d  > ord('Z'):
         print(chr((ord(temp)+d-ord('A'))%26+ord('A')),end = '')
      else :
         print(chr((ord(temp)+d)),end='')
      d=d+1
d=i-1
while d>=0:
      if ord(temp)+ d  > ord('Z'):
         print(chr((ord(temp) + d - ord('A')) % 26 + ord('A')), end='')
      else:
      print(chr((ord(temp)+d)),end = '')
      d=d-1
print('\n',end='')
i=i+1

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