[已解决]python爬豆瓣图书毫无反应，也没报错

suishoufang

爬虫代码：
import requests
import re
content = requests.get('https://book.douban.com/').text
pattern = re.compile('<li.?cover.?href="(.?)".?title="(.?)".?more-meta.?author">(.?)</span>.?year">(.?)</span>.*?<li>',re.S)
results = re.findall(pattern,content)
print(results)
for result in results:

url,name,author,date = result
author = re.sub('\s',author)
date = re.sub('\s','',date)
print(url,name,author,date)

执行一直显示在执行，但毫无结果，也没报错，等一个小时还在执行，求大神帮忙看看问题出在哪

最佳答案

月排行榜 / 总排行榜

ba21

2018-3-28 20:23:22

一看就知道正则没写对， 看下面代码的正则：

1. import requests
   
2. import re
   
3. content = requests.get('https://book.douban.com/').text
   
4. pattern = re.compile(r'<li class="">.*?<div class="cover">.*?<a href="(.+?)" title="(.+?)".*?<span class="author">(.+?)</span>.*?<span class="year">(.+?)</span>.*?</li>',re.S)
   
5. results = re.findall(pattern,content)
   
6. 
   
7. 
   
8. for result in results:
   
9.     url,name,author,date = result
   
10.    
    
11.    
    
12.     print(url)
    
13.     print(name)
    
14.     print(author)
    
15.     print(date)
    
16. 
    
17. 
    

复制代码

跳转到最佳答案楼层

wongyusing

你的格式有问题
for result in results:
下面的代码不用缩进？？？
还是说你没有按照格式发帖？

ba21

一看就知道正则没写对， 看下面代码的正则：

1. import requests
   
2. import re
   
3. content = requests.get('https://book.douban.com/').text
   
4. pattern = re.compile(r'<li class="">.*?<div class="cover">.*?<a href="(.+?)" title="(.+?)".*?<span class="author">(.+?)</span>.*?<span class="year">(.+?)</span>.*?</li>',re.S)
   
5. results = re.findall(pattern,content)
   
6. 
   
7. 
   
8. for result in results:
   
9.     url,name,author,date = result
   
10.    
    
11.    
    
12.     print(url)
    
13.     print(name)
    
14.     print(author)
    
15.     print(date)
    
16. 
    
17. 
    

复制代码