[已解决]多重列表的读取

jfmlj

有个多重列表，比如

[['1045123'], ['1045123', '0'], ['1292848462', '5'], ['5'], ['4', '126', '1', '2', '2', '18588343581208995', '130', '130'], ['45236'], ['45236', '0'], ['5'], ['4', '126', '6', '30', '8', '32', '1368891985494394', '130', '130'], ['27604'], ['27604', '0'], ['5'], ['3', '126', '71', '6', '7', '6037418348748276', '130', '130'], ['196215'], ['196215', '0'], ['5'], ['3', '126', '7', '3', '1390882221525719', '130', '130'], ['1035020'], ['1035020', '0'], ['550130477', '5'], ['5'], ['4', '126', '13', '384', '28', '48', '18719185464564514', '130', '130'], ['29251'], ['29251', '0'], ['377929021', '5'], ['5'], ['4', '126', '6', '3', '4', '304564720905658', '130', '130'], ['27595'], ['27595', '0'], ['5'], ['3', '126', '6', '6', '109951163053010010', '130', '130'], ['27621'], ['27621', '0'], ['351218439', '5'], ['5'], ['4', '126', '6', '7', '19174383277072780', '130', '130'], ['28727'], ['28727', '0'], ['5'], ['3', '126', '5', '7', '8', '6635552675435785', '130', '130'], ['1046359'], ['1046359', '0'], ['28745', '0'], ['28690', '0'], ['47425', '0'], ['29100', '0']]

我想通过递归把所有的内容读取到一个列表中，即去多重

def p(a):
        b=[]
        for i in a:
                if isinstance(i,list):
                        p(i)
                else:
                        print(i)
                        b.append(i)
        return b

为什么返回的列表是空的？要怎么修改？
或者还有什么其他更方便的读取方法？

最佳答案

月排行榜 / 总排行榜

第四时空

2018-4-12 11:42:25

第一感觉难道不是把里面中括号去掉就好了嘛

1. if __name__ == "__main__":
   
2.     li = [
   
3.         ['1045123'], ['1045123', '0'], ['1292848462', '5'], ['5'],
   
4.         ['4', '126', '1', '2', '2', '18588343581208995', '130', '130'],
   
5.         ['45236'], ['45236', '0'], ['5'],
   
6.         ['4', '126', '6', '30', '8', '32', '1368891985494394', '130', '130'],
   
7.         ['27604'], ['27604', '0'], ['5'], ['3', '126', '71', '6', '7', '6037418348748276', '130', '130'],
   
8.         ['196215'], ['196215', '0'], ['5'], ['3', '126', '7', '3', '1390882221525719', '130', '130'],
   
9.         ['1035020'], ['1035020', '0'], ['550130477', '5'], ['5'],
   
10.         ['4', '126', '13', '384', '28', '48', '18719185464564514', '130', '130'],
    
11.         ['29251'], ['29251', '0'], ['377929021', '5'], ['5'],
    
12.         ['4', '126', '6', '3', '4', '304564720905658', '130', '130'],
    
13.         ['27595'], ['27595', '0'], ['5'], ['3', '126', '6', '6', '109951163053010010', '130', '130'],
    
14.         ['27621'], ['27621', '0'], ['351218439', '5'], ['5'],
    
15.         ['4', '126', '6', '7', '19174383277072780', '130', '130'], ['28727'],
    
16.         ['28727', '0'], ['5'], ['3', '126', '5', '7', '8', '6635552675435785', '130', '130'],
    
17.         ['1046359'], ['1046359', '0'], ['28745', '0'], ['28690', '0'], ['47425', '0'], ['29100', '0']
    
18.     ]
    
19.     new_li = eval("[{}]".format(str(li).replace("[", "").replace("]", "")))
    
20.     print(new_li)

复制代码

跳转到最佳答案楼层

BngThea

def p(a):
        b = []
        for each in a:
                for i in each:
                        b.append(i)
        return set(b)

jfmlj

BngThea 发表于 2018-4-12 11:29
def p(a):
        b = []
        for each in a:

这个只是2重，我实际的数据里有3，4重，个别更高，

第四时空

第一感觉难道不是把里面中括号去掉就好了嘛

1. if __name__ == "__main__":
   
2.     li = [
   
3.         ['1045123'], ['1045123', '0'], ['1292848462', '5'], ['5'],
   
4.         ['4', '126', '1', '2', '2', '18588343581208995', '130', '130'],
   
5.         ['45236'], ['45236', '0'], ['5'],
   
6.         ['4', '126', '6', '30', '8', '32', '1368891985494394', '130', '130'],
   
7.         ['27604'], ['27604', '0'], ['5'], ['3', '126', '71', '6', '7', '6037418348748276', '130', '130'],
   
8.         ['196215'], ['196215', '0'], ['5'], ['3', '126', '7', '3', '1390882221525719', '130', '130'],
   
9.         ['1035020'], ['1035020', '0'], ['550130477', '5'], ['5'],
   
10.         ['4', '126', '13', '384', '28', '48', '18719185464564514', '130', '130'],
    
11.         ['29251'], ['29251', '0'], ['377929021', '5'], ['5'],
    
12.         ['4', '126', '6', '3', '4', '304564720905658', '130', '130'],
    
13.         ['27595'], ['27595', '0'], ['5'], ['3', '126', '6', '6', '109951163053010010', '130', '130'],
    
14.         ['27621'], ['27621', '0'], ['351218439', '5'], ['5'],
    
15.         ['4', '126', '6', '7', '19174383277072780', '130', '130'], ['28727'],
    
16.         ['28727', '0'], ['5'], ['3', '126', '5', '7', '8', '6635552675435785', '130', '130'],
    
17.         ['1046359'], ['1046359', '0'], ['28745', '0'], ['28690', '0'], ['47425', '0'], ['29100', '0']
    
18.     ]
    
19.     new_li = eval("[{}]".format(str(li).replace("[", "").replace("]", "")))
    
20.     print(new_li)

复制代码

jfmlj

第四时空 发表于 2018-4-12 11:42
第一感觉难道不是把里面中括号去掉就好了嘛

晕，傻逼了我

第四时空

jfmlj 发表于 2018-4-12 11:43
晕，傻逼了我

我开玩笑的，没想到被采纳了。这个方法其实不好。
如果列表里是对象呢？那就GG了。
还是用递归的方式好些，可以参考下这个帖子里的github高质量函数分享。里面前几个就有多维列表转一维的方法。
http://bbs.fishc.com/thread-105766-1-1.html

BngThea

jfmlj 发表于 2018-4-12 11:35
这个只是2重，我实际的数据里有3，4重，个别更高，

1. def p(a):
   
2.     b=[]
   
3.     for i in a:
   
4.         if isinstance(i,list):
   
5.             b.extend(p(i))
   
6.         else:
   
7.             #print(i)
   
8.             b.append(i)
   
9.     return b

复制代码

graceasyi

都是字符串，我就这样想了，不过只能处理二维列表……

1. tmp=[]
   
2. for each in li:
   
3.     tmp += each
   
4. print(tmp)

复制代码

jfmlj

嗯嗯，看了大家的回复，很有启发，谢谢