Python：每日一题 197

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题目：
已知有如下的变量

1. var1 = 5
   
2. var2 = "Python"
   
3. var3 = 3.14
   
4. var4 = 5 * 12.33
   
5. var5 = [1, 1, 2, 3, 5, 8]

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要求使用循环将上述变量print出来。


==============================
本题是想考察大家对globals()和locals()的理解，python中每个变量、函数、类等的名字和值都存放在一个字典中，且名字是已字符串的形式表示。通过操纵字典可以取值赋值。

零度冷咖啡

1. var1 = 5
   
2. var2 = "Python"
   
3. var3 = 3.14
   
4. var4 = 5 * 12.33
   
5. var5 = [1, 1, 2, 3, 5, 8]
   
6. a = [var1,var2,var3,var4,var4,var5]
   
7. for  i in a:
   
8.     print(i)

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这样好么！！！

塔利班

1. i,j=0,0
   
2. for i,j in list(locals().items())[-7:-2]:
   
3.     print(i,':',j)

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JessiFly

1. var1 = 5
   
2. var2 = "Python"
   
3. var3 = 3.14
   
4. var4 = 5 * 12.33
   
5. var5 = [1, 1, 2, 3, 5, 8]
   
6. 
   
7. var_names = []
   
8. for i in range(1,6):
   
9.     var_name = 'var' + str(i)
   
10.     var_names.append(var_name)
    
11. 
    
12. for each in var_names:
    
13.     print(eval(each))

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阿翔天明

>>> var1 = 1
>>> var2 = "Python"
>>> var3 = 3.14
>>> var4 = 5 * 12.33
>>> var5 = [1,1,2,3,5,8]
>>> list1 = [var1,var2,var3,var4,var5]
>>> for each in list1:
        print(each,end='\n')

       
1
Python
3.14
61.65
[1, 1, 2, 3, 5, 8]

CC柴

怎么赶脚是我理解错了

1. var1 = 5
   
2. var2 = "Python"
   
3. var3 = 3.14
   
4. var4 = 5*12.33
   
5. var5 = [1,1,2,3,5,8]
   
6. list1 = [var1,var2,var3,var4,var5]
   
7. for i in list1:
   
8.     print(i)

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可乐必须加冰

不知道理解的对不对，总觉得不应该这么简单……

1. dic = {"var1": var1, "var2": var2, "var3": var3, "var4": var4, "var5": var5}
   
2. for key, value in dic.items():
   
3.     print(key, "=" , value)

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ErTian

var1 = 5
var2 = "python"
var3 = 3.14
var4 = 5 * 12.33
var5 = [1, 1, 2, 3, 5, 8]


def test197(*args):
    for i in args:
        print(i)

test197(var1,var2,var3,var4,var5)

凌九霄

1. vars = locals()
   
2. for i in range(1, 6):
   
3.     print(vars[ 'var' + str(i) ])

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lvvly

lst = []
var1 = 5
var2 = "Python"
var3 = 3.14
var4 = 5 * 12.33
var5 = [1, 1, 2, 3, 5, 8]
lst.append(var1)
lst.append(var2)
lst.append(var3)
lst.append(var4)
lst.append(var5)
for i in range(len(lst)):
    print(lst[i])

virgilchao

def print_197():
    var1 = 5
    var2 = "Python"
    var3 = 3.14
    var4 = 5 * 12.33
    var5 = [1, 1, 2, 3, 5, 8]
    names=locals()
   
    for i in range(5):
        print(names['var'+str(i+1)])

if __name__ == '__main__':
    print_197()

chongchuigu

1. def a197():
   
2.         var1 = 5
   
3.         var2 = "Python"
   
4.         var3 = 3.14
   
5.         var4 = 5 * 12.33
   
6.         var5 = [1, 1, 2, 3, 5, 8]
   
7.         counter=1
   
8.         for i in range(5):
   
9.                 print(eval('var'+str(counter)))
   
10.                 counter+=1
    
11. a197()
    

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拉了盏灯

1. var1 = 5
   
2. var2 = "Python"
   
3. var3 = 3.14
   
4. var4 = 5 * 12.33
   
5. var5 = [1, 1, 2, 3, 5, 8]
   
6. for i in range(5):
   
7.         if i == 0:
   
8.                 print(var1)
   
9.         if i == 1:
   
10.                 print(var2)
    
11.         if i == 2:
    
12.                 print(var3)
    
13.         if i == 3:
    
14.                 print(var4)
    
15.         if i == 4:
    
16.                 print(var5)

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Ant_

var1 = 5
var2 = "Python"
var3 = 3.14
var4 = 5 * 12.33
var5 = [1, 1, 2, 3, 5, 8]
var=[var1,var2,var3,var4,var5]
for i in var:
    print(i)

久疤K

1. 不知道我对这个题的理解是否有误~
   
2. >>> var1 = 5
   
3. >>> var2 = "Python"
   
4. >>> var3 = 3.14
   
5. >>> var4 = 5 * 12.33
   
6. >>> var5 = [1, 1, 2, 3, 5, 8]
   
7. >>> def fun( ls ):
   
8.         i = 1
   
9.         while True:
   
10.                 t = "var"+str(i)
    
11.                 if t in ls:
    
12.                         print(eval(t))
    
13.                 else:
    
14.                         break
    
15.                 i += 1
    
16. 
    
17.                
    
18. >>> fun(dir())
    
19. 5
    
20. Python
    
21. 3.14
    
22. 61.65
    
23. [1, 1, 2, 3, 5, 8]
    
24. >>>

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天圆突破

1. var1 = 5
   
2. var2 = "Python"
   
3. var3 = 3.14
   
4. var4 = 5 * 12.33
   
5. var5 = [1, 1, 2, 3, 5, 8]
   
6. 
   
7. #方法 1
   
8. for i in range(1,6):
   
9.     print(eval("var%d"%i))
   
10. 
    
11. #方法2
    
12. for i in range(2,6):
    
13.     print(globals()["var%d"%i])
    
14. 
    
15. #方法 3
    
16. for i in range(2,6):
    
17.     print(locals()["var%d"%i])
    
18. 
    
19. #方法 4
    
20. bar = type("bar",(), {"var%d"%i:globals()["var%d"%i] for i in range(1,6)})
    
21. for i in range(1,6):
    
22.     print(getattr(bar, "var%d"%i))

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1. 回字有四种写法.....

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zhou995287902

1. var1 = 5
   
2. var2 = "Python"
   
3. var3 = 3.14
   
4. var4 = 5 * 12.33
   
5. var5 = [1, 1, 2, 3, 5, 8]
   
6. for i in range(1,6):
   
7.     var='var'+str(i)
   
8.     print(locals()[var])
   

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祥哥威武

1. def func0():
   
2.     yield 5
   
3.     yield "python"
   
4.     yield 3.14
   
5.     yield 5 * 12.33
   
6.     yield [1, 1, 2, 3, 5, 8]
   
7. for i in func0():
   
8.     print(i)

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Henriz

1. var1 = 5
   
2. var2 = "Python"
   
3. var3 = 3.14
   
4. var4 = 5 * 12.33
   
5. var5 = [1, 1, 2, 3, 5, 8]
   
6. 
   
7. for i in range(1,6):
   
8.     print(eval("var%s"%i))
   

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bigoldli

var1 = 5
var2 = "Python"
var3 = 3.14
var4 = 5 * 12.33
var5 = [1, 1, 2, 3, 5, 8]

name = locals()
for i in range(1, 6):
    print(name['var' + str(i)])