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[已解决]020讲:函数:内嵌函数和闭包动动手最后一题

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发表于 2018-9-2 21:15:08 | 显示全部楼层 |阅读模式

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本帖最后由 白无痕 于 2018-9-2 21:34 编辑

.请用已学过的知识编写程序,找出小甲鱼藏在下边这个长字符串中的密码,密码的埋藏点符合以下规律:
    a) 每位密码为单个小写字母
    b) 每位密码的左右两边均有且只有三个大写字母

以下是我打得代码,就是不知道问题出在哪了,运行结果总是多出两个字母,求大神为小弟解惑

  1. str1 = '题目的字符串'
  2. x = 0
  3. y = 9

  4. for i in range(len(str1)-10):

  5.             
  6.     if str1[x+4].islower() and str1[x+1:x+4].isupper() and str1[y-4:y-1].isupper()and not str1[x].isupper() and not str1[y-1].isupper():
  7.         print(str1[x+4],end = '')
  8.         x += 1
  9.         y += 1
  10.     else:
  11.         x += 1
  12.         y += 1
复制代码



字符串:
ACFlCTLIQlAIVMTqHFkswqbDDHtpgcWaXSSglUYKE
lqNsYCyaQXBzrFUbkAUAWAKrDgDtAlGMBqWQhpEwquZqWZJpslUfMllCwWptqINjrOBTLuPzwvXNbLCx
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最佳答案
2018-9-3 23:48:07
本帖最后由 geen 于 2018-9-3 23:50 编辑

这个问题之前有鱼油问过了,戳链接:https://fishc.com.cn/forum.php?m ... p;page=1#pid3523406

主要是换行符 \n 的问题,
用SHELL检验下,的确也如此:
>>> str1 = 'AA\nA'
>>> print(str1[0:3].isupper())
True
>>> print(str1[0:2].isupper())
True
>>> len(str1)
4
>>>
小甲鱼最新课程 -> https://ilovefishc.com
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发表于 2018-9-2 21:21:44 | 显示全部楼层
原本的字符串呢?
小甲鱼最新课程 -> https://ilovefishc.com
回复 支持 反对

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 楼主| 发表于 2018-9-2 21:35:04 | 显示全部楼层
claws0n 发表于 2018-9-2 21:21
原本的字符串呢?

字符串来了
小甲鱼最新课程 -> https://ilovefishc.com
回复 支持 反对

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发表于 2018-9-3 07:08:58 | 显示全部楼层
字符串有换行,不知道你考虑了没
小甲鱼最新课程 -> https://ilovefishc.com
回复 支持 反对

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发表于 2018-9-3 23:48:07 | 显示全部楼层    本楼为最佳答案   
本帖最后由 geen 于 2018-9-3 23:50 编辑

这个问题之前有鱼油问过了,戳链接:https://fishc.com.cn/forum.php?m ... p;page=1#pid3523406

主要是换行符 \n 的问题,
用SHELL检验下,的确也如此:
>>> str1 = 'AA\nA'
>>> print(str1[0:3].isupper())
True
>>> print(str1[0:2].isupper())
True
>>> len(str1)
4
>>>
小甲鱼最新课程 -> https://ilovefishc.com
回复 支持 反对

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