如何实现文件路径的选择,并将选择的文件路径填写到textbox文本框中

江老师实验室

from tkinter import *
from tkinter.filedialog import askdirectory
root=Tk()
Label(root, text ="上传图片：").grid(row=0,column=0)
Label(root, text ="识别结果：").grid(row=1,column=0)

path1 = StringVar(root, value='')
e1 = Entry(root, textvariable=path1, font=('微软雅黑',12))
e1.grid(row=0,column=1,padx=10,pady=5)

v2 = StringVar(root, value='')
e2 = Entry(root, textvariable=v2, font=('微软雅黑',12))
e2.grid(row=1,column=1,padx=10,pady=5)
#def show():
def selectPath():
    path_ = askdirectory()
    path.set(path_)
Button(root,text="开始识别",width=10,command=show).grid(row=3,column=0,sticky=W,padx=10,pady=5)
Button(root,text="退出",width=10,command=root.quit).grid(row=3,column=1,sticky=E,padx=10,pady=5)
Button(root,text="路径选择",width=10,command=selectPath).grid(row=0,column=2,sticky=E,padx=10,pady=5)



mainloop()
如何实现文件路径的选择,并将选择的文件路径填写到textbox文本框中

塔利班

from tkinter import *
from tkinter.filedialog import askdirectory
root=Tk()

def selectPath():
    path = askdirectory()
    tt.insert(END,path+'\n')

Button(root,text="路径选择",width=10,command=selectPath).grid(row=0,padx=10,pady=5)
tt=Text(root,width=30)
tt.grid(row=1,padx=10,pady=5)
mainloop()

塔利班

感觉askopenfilename才是对的控件，因为你要打开图片识别不是么

from tkinter import *
from tkinter.filedialog import askopenfilename
root=Tk()

def selectPath():
    path = askopenfilename(filetypes=[("bmp格式","bmp"),("jpg格式","jpg"),("png格式","png")])
    tt.insert(END,path+'\n')

Button(root,text="路径选择",width=10,command=selectPath).grid(row=0,padx=10,pady=5)
tt=Text(root,width=30)
tt.grid(row=1,padx=10,pady=5)
mainloop()