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实验五 6小题:
我做得解答:- assume cs:code
- a segment
- db 1,2,3,4,5,6,7,8
- a ends
- b segment
- db 1,2,3,4,5,6,7,8
- b ends
- c segment
- db 0,0,0,0,0,0,0,0
- c ends
- code segment
-
- start:
-
- mov ax,a
- mov es,ax
-
- mov ax,c
- mov ds,ax
-
- mov bx,0
- mov cx,8
-
- s0:
- mov al,es:[bx]
- mov [bx],al
- inc bx
- loop s0
-
- mov ax,b
- mov es,ax
-
- mov ax,c
- mov ds,ax
-
- mov bx,0
- mov cx,8
-
- s1:
- mov al,es:[bx]
- add [bx],al
- inc bx
- loop s1
-
-
- mov ax,4c00h
- int 21h
- code ends
- end start
复制代码 网上的答案:- assume cs:code
-
- a segment
- db 1,2,3,4,5,6,7,8
- a ends
-
- b segment
- db 1,2,3,4,5,6,7,8
- b ends
-
- c segment
- db 0,0,0,0,0,0,0,0
- c ends
-
- code segment
- start:mov ax,a
- mov es,ax
- mov ax,c
- mov ds,ax
- mov bx,0
- mov cx,8
-
- s1:mov ax,es:[bx]
- add [bx],ax
- add bx,2
- loop s1
-
- mov ax,b
- mov es,ax
- mov ds,ax
- mov bx,0
- mov cx,8
-
- s2:mov ax,es:[bx]
- add [bx],ax
- add bx,2
- loop s2
-
- mov ax,4c00h
- int 21h
- code ends
- end start
复制代码 都能正确运行,为什么
s2:mov ax,es:[bx]
add [bx],ax
add bx,2
能正确运行
如果偏移了两个单元,后续的第二个单元怎么会正确取出数据 |