txt文件中包含列表的个数

zby0709

逐行检测txt文件中包含 meat元祖的个数 输出个数总和

with open('market basket.txt','r')as f:
    meat = ['beef','pork','turkey','chicken']
    num = 0
    while True:
        lines = f.readline()
        data = [str(line) for line in lines.split(',')]
        for i in data:
            if i in meat:
                num+=1
        if not lines:
            break

print('The number of baskets containing meat is: ',num)

TCY

1. import re
   
2. 
   
3. with open('market basket.txt','r')as f:
   
4.     lines = f.read()
   
5.     beef = re.findall(r"(?:beef)+", lines)
   
6.     pork = re.findall(r"(?:pork)+", lines)
   
7.     turkey = re.findall(r"(?:turkey)+", lines)
   
8.     chicken = re.findall(r"(?:turkey)+", lines)
   
9.     num = len(beef) + len(pork) + len(turkey) + len(chicken)
   
10.             
    
11. print('The number of baskets containing meat is: ',num)

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TCY

逐行太麻烦，直接求出来即可

zby0709

TCY 发表于 2018-11-22 18:30
逐行太麻烦，直接求出来即可

因为原文件是分行的 有的一行里包含多个单词

喜欢吃菠菜

参考一下：

1. def count_words_in_file(filename,wordlist):
   
2.     import re
   
3.     with open(filename) as f:
   
4.         pat=re.compile(r'\b'+r'\b|'.join(wordlist)+r'\b',re.RegexFlag.I)
   
5.         return len(pat.findall(f.read()))
   
6. 
   
7. print('The number of baskets containing meat is:count_words_in_file('makes_basket.txt',['beef','pork','turkey','chicken']))

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