[已解决]求教解决方法

WRHao

import pickle

m = 0
#def date_pkl_create():
    #date = {1:31,2:28,3:31,4:30,5:31,6:30,7:31,8:31,9:30,10:31,11:30,12:31}
    #pickle_file = open('date.pkl','wb')
    #pickle.dump(dict,pickle_file)
    #pickle_file.close()
def isLeapYear(a):
    if (0 == a%4 or 0 == a%400) and 0 != a%100:
        return 1
    else:
        return 0
def date_search():
    pickle_file = open('date.pkl','rb')
    date = pickle.load(pickle_file)
    a = int(input("Input year:"))
    b = int(input("Input month:"))
    c = int(input("Input day:"))
    k = isLeapYear(a)
    for i in range(1,b):
        d = date[i]
    m = m+k+d+c
         
print(m)

代码只显示这个，请问是怎么回事呀
RESTART: C:\Users\AppData\Local\Programs\Python\Python37\实例2_日期判断(pickle).py
0

最佳答案

月排行榜 / 总排行榜

塔利班

2019-3-7 20:33:39

你函数定义了没有执行，就打印了0

跳转到最佳答案楼层

塔利班

你函数定义了没有执行，就打印了0

WRHao

塔利班 发表于 2019-3-7 20:33
你函数定义了没有执行，就打印了0

脑子瓦特了，万分感谢