[已解决]这种改进如何改进呢~

QQ27891996

print("欢迎进行python文字的第三次文字游戏改进测试")
temp = input("please fall a number in the bank")
guess = int(temp)
while guess != 8:
    chance = 3
    chance = chance -1
    if guess >8:
        print("bigger than answer")
    else :
        print("smaller than answer")

    temp = input("please try again ")
    guess =int(temp)
print("you are right")
input("The game is over!")
while chance == 0:
    print("sorry, you have 3 times to answer this question")
input("the game is over")

最佳答案

月排行榜 / 总排行榜

冬雪雪冬

2019-6-2 19:55:21

print("欢迎进行python文字的第三次文字游戏改进测试")
temp = input("please fall a number in the bank")
guess = int(temp)
chance = 2
while chance != 0:
    
    
    if guess >8:
        print("bigger than answer")
    elif guess <8:
        print("smaller than answer")
    else:
        break
    temp = input("please try again ")
    guess =int(temp)
    chance = chance -1
if guess != 8:
    print("sorry, you have 3 times to answer this question")
else:
    print("you are right")
print("The game is over!")

跳转到最佳答案楼层

QQ27891996

英语有点烂，不要介意。

QQ27891996

我想让chance = 0的时候，就结束这个游戏，
但是 好像while 一直重复的时候，会反复运行chance = 3
这就会导致一直退不出去。

冬雪雪冬

print("欢迎进行python文字的第三次文字游戏改进测试")
temp = input("please fall a number in the bank")
guess = int(temp)
chance = 2
while chance != 0:
    
    
    if guess >8:
        print("bigger than answer")
    elif guess <8:
        print("smaller than answer")
    else:
        break
    temp = input("please try again ")
    guess =int(temp)
    chance = chance -1
if guess != 8:
    print("sorry, you have 3 times to answer this question")
else:
    print("you are right")
print("The game is over!")

QQ27891996

冬雪雪冬 发表于 2019-6-2 19:55

谢谢大佬，原来要先做一个while的机会语句。

迷茫的兔子

import random
#获取1-30的随机数quession
quession = random.randint(1,30)
#定义while循环标记
active = True
while active:
    #定义次数计数器
    for i in range(6,0, -1):
        #获取用户输入
        answer = int(input("请输入1-30的整数回答问题："))
        print('目前还有%d次猜测机会!' % i)
        if answer > quession:
            print("猜大了，请努力")
        elif answer < quession:
            print("猜小了，请努力")
        elif answer == quession:
            print("真棒，回答正确！正确答案为%d ." % quession)
            #如果用户回答正确，重置while标记退出循环
            active = False
            break
    #猜测次数用完后，判断用户是否想继续游戏        
    else:
        count = input("目前已经没有回答机会，请问是否放弃游戏[y/n]：")
        if count == "n":
            continue
        else:
            break
            
这是我的猜数代码，有兴趣可以参考下