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5鱼币
本帖最后由 方大侠 于 2019-6-16 17:02 编辑
protected的访问类别:这个类及其子类;
- #include <iostream>
- #include <string>
- class Animal
- {
- public:
- Animal(std::string theName);
- void eat();
- void eat(int num);
- protected:
- std::string name;
- };
- class Pig : public Animal
- {
- public:
- Pig(std::string theName);
- void climb();
- };
- Animal::Animal(std::string theName)
- {
- name = theName;
- }
- void Animal::eat()
- {
- std::cout << "I'm eatting!" << std::endl;
- }
- void Animal::eat(int num) //eat()函数重载
- {
- std::cout << "I'm eatting" << num << "碗混沌" << std::endl;
- }
- void Animal::sleep()
- {
- std::cout << "I'm sleeping!Don't disturb me!\n" << std::endl;
- }
- void Animal::drool()
- {
- std::cout << "我是公的,看到母的我会流口水,我正在流口水。。。\n" << std::endl;
- }
- Pig::Pig(std::string theName) : Animal(theName)
- {
- }
- void Pig::climb()
- {
- std::cout << "我是一个只漂亮的小母猪猪,我会上树,我正在爬树,嘘。。。\n" << std::endl;
- }
- int main()
- {
- Pig pig("小猪猪");
- std::cout << "这只猪的名字是: " << pig.name << std::endl; // 错误
- pig.eat();
- pig.eat(15);
- pig.climb();
- return 0;
- }
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问题主要在:
std::cout << "这只猪的名字是: " << pig.name << std::endl; // 编译错误
3.cpp:87:51: error: 'name' is a protected member of 'Animal'
std::cout << "这只猪的名字是: " << pig.name << std::endl...
^
3.cpp:14:17: note: declared protected here
std::string name;
^
1 error generated.
因为是protected,所以子类不能访问???
要输出名字name,只能写一个函数吗??
比如
- std::string pig::get_name(){
- return name;
- }
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