[已解决]MAX和匿名函数混用的一个疑问

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MAX函数中只能比较相同的数据类型,如果要比较以下的数据,则需要传入一个key属性

1. a = [{"name":"alex","age":100},
   
2. {"name":"blex","age":200},
   
3. {"name":"clex","age":300},
   
4. {"name":"dlex","age":400},]
   
5. print(max(a,key=lambda x:x["age"]))

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输出结果为: {'age': 400, 'name': 'dlex'}


想请问下如果要自定义函数也输出  {'age': 400, 'name': 'dlex'}  这个结果,
这个函数该怎么写.

最佳答案

月排行榜 / 总排行榜

冬雪雪冬

2019-6-23 21:59:56

1. a = [{"name":"alex","age":100},
   
2. {"name":"blex","age":200},
   
3. {"name":"clex","age":300},
   
4. {"name":"dlex","age":400},]
   
5. def mymax(dic):
   
6.     name = ''
   
7.     age = float('-inf')
   
8.     for each in dic:
   
9.         if each['age'] > age:
   
10.             age = each['age']
    
11.             name = each['name']
    
12.     return {'name': name, 'age': age}

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跳转到最佳答案楼层

冬雪雪冬

1. a = [{"name":"alex","age":100},
   
2. {"name":"blex","age":200},
   
3. {"name":"clex","age":300},
   
4. {"name":"dlex","age":400},]
   
5. def mymax(dic):
   
6.     name = ''
   
7.     age = float('-inf')
   
8.     for each in dic:
   
9.         if each['age'] > age:
   
10.             age = each['age']
    
11.             name = each['name']
    
12.     return {'name': name, 'age': age}

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