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发表于 2022-12-26 18:16:41
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本帖最后由 hveagle 于 2022-12-26 18:32 编辑
非2022年来观看的人注意改一下有注释的地方,并且去掉注释
- eachmonth = [0,31,28,31,30,31,30,31,31,30,31,30,31]
- week = ['下标为0, 占个位', '星期日', '星期一', '星期二', '星期三', '星期四', '星期五', '星期六']
- from tkinter import *
- root = Tk()
- def is366(n):
- if (n % 4 == 0 and n % 100) or n % 400 == 0:
- return True
- else:
- return False
- def whatday(year, month, day):
- num366 = 0
- if year >= 2022:#改成相对年份
- if year >= 2024:#改成相对年份的下一个闰年
- for each in range(2024#改成相对年份的下一个闰年, year+1, 4):
- if is366(each):
- num366 += 1
- if is366(year) and month < 3:
- num366 -= 1
- deltday = (year - 2022#改成相对年份)*365 + sum(eachmonth[:month]) + (day -1) + num366
- return (deltday-1) % 7
- else:
- if year <= 2020:#改成相对年份的上一个闰年
- for each in range(year, 2022#改成相对年份, 4):
- if is366(each):
- num366 += 1
- if is366(year) and month >= 3:
- num366 -= 1
- deltday = (year - 2022#改成相对年份)*365 + sum(eachmonth[:month]) + (day -1) - num366
- return (deltday-1) % 7
- class Date:
- def __init__(self, y, m, d):
- self.y = y
- self.m = m
- self.d = d
- self.w = whatday(self.y, self.m, self.d)
- self.row = (self.d + bnum)//7 +2 if (self.d + bnum)%7 else (self.d + bnum)//7 + 1
- data = []
- y = int(input('请输入年:'))
- m = int(input('请输入月:'))
- em = eachmonth[m]
- bnum = whatday(y, m, 1)
- if m == 2:
- if is366(y):
- em = 29
- for i in range(1, em+1):
- data.append(Date(y, m, i))
- Label(root, text=f'{y}年', fg='blue').grid(row=0, column=2)
- Label(root, text=f'{m}月', fg='blue').grid(row=0, column=4)
- i = -1
- j = 0
- while i < 6:
- while j < 7:
- i += 1
- j += 1
- Label(root, text=week[j], fg='red').grid(row=1, column=i)
- for each in data:
- if each.w == 6 or each.w == 0:
- Label(root, text=str(each.d), fg='red').grid(row=each.row, column=each.w)
- else:
- Label(root, text=str(each.d)).grid(row=each.row, column=each.w)
- mainloop()
复制代码
42行普通敢对我61行tkinter吗? |
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