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斐波那契数列的应用
You are climbing a stair case. It takes n steps to reach to the top.
Each time you can either climb 1 or 2 steps. In how many distinct ways can you climb to the top?
Note: Given n will be a positive integer.
Example 1:
Input: 2
Output: 2
Explanation: There are two ways to climb to the top.
1. 1 step + 1 step
2. 2 steps
Example 2:
Input: 3
Output: 3
Explanation: There are three ways to climb to the top.
1. 1 step + 1 step + 1 step
2. 1 step + 2 steps
3. 2 steps + 1 step
class Solution {
public int climbStairs(int n) {
int[] array = new int[n+1];
array[0] = 1;
array[1] = 1;
for(int i = 2 ; i <= n ; i++){
array[i] = array[i -1] + array[i -2];
}
return array[n];
}
}
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