关于PYTHON发送邮件的问题

zcsxbjzc

请问：这段发送邮件的代码为什么没有标题和发件人。发送后，不显示标题和发送人。




import smtplib
from email.mime.base import MIMEBase
from email.mime.multipart import MIMEMultipart
from email.mime.text import MIMEText
from email.mime.image import MIMEImage
from email.mime.application import MIMEApplication

mail_host =('smtp.exmail.qq.com')
port =465
send_by = ('a@au.com')
password = ('a')
send_to = ('278597602@qq.com')




def send_mail(title,content,):
    m=MIMEText(content,'plain','utf-8')
    m["From"] = send_by
    m["To"] = send_to
    m["Subjest"] = title
    #文本
    textApart=MIMEText(content)
   

    # docx文档
    docxFile = 'D:/西部视点.docx'
    docxApart = MIMEApplication(open(docxFile, 'rb').read())
    docxApart.add_header('Content-Disposition', 'attachment', filename=docxFile)

     
    #将其附件加入到发送目标
    m = MIMEMultipart()
    m.attach(textApart)
    m.attach(docxApart)
    #登录
    try:
        smpt=smtplib.SMTP_SSL(mail_host,port,'utf-8')
        smpt.login(send_by,password)
        smpt.sendmail(send_by,send_to,m.as_string())
        print('success!')
    except smtplib.SMTPException as e:
        print('Error:',e)

if __name__=="__main__":
    title='Test'
    content='恭喜你收到邮件！'
    send_mail(title,content)

傻纸

不太清楚你出现问题的原因，但是我这样写貌似是可以

1. import smtplib
   
2. from email.mime.text import MIMEText
   
3. 
   
4. msg = MIMEText("准备好开学了吗，暑假过得怎么样？","plain","utf-8")
   
5. msg['Subject'] = ("来自学校的问候")
   
6. msg['From'] = "teacher<XXX@163.com>"
   
7. msg['To'] = "XXXX@qq.com"
   
8. 
   
9. s=smtplib.SMTP_SSL('smtp.163.com',465,'utf-8')
   
10. 
    
11. s.login("XXX@163.com","password")
    
12. s.sendmail("XXX@163.com","XXXX@qq.com",msg.as_string())
    
13. s.quit()
    

复制代码

我这是从网易到腾讯邮箱。一般太长的代码不太好看，你就可以简化一下，比方在不传doc的时候试一下，就简单发送一下邮件，几行代码，也比较好找问题...

塔利班

还是yagmail简单点