|
马上注册,结交更多好友,享用更多功能^_^
您需要 登录 才可以下载或查看,没有账号?立即注册
x
- Given an array nums and a value val, remove all instances of that value in-place and return the new length.
- Do not allocate extra space for another array, you must do this by modifying the input array in-place with O(1) extra memory.
- The order of elements can be changed. It doesn't matter what you leave beyond the new length.
- Example 1:
- Given nums = [3,2,2,3], val = 3,
- Your function should return length = 2, with the first two elements of nums being 2.
- It doesn't matter what you leave beyond the returned length.
- Example 2:
- Given nums = [0,1,2,2,3,0,4,2], val = 2,
- Your function should return length = 5, with the first five elements of nums containing 0, 1, 3, 0, and 4.
- Note that the order of those five elements can be arbitrary.
- It doesn't matter what values are set beyond the returned length.
- Clarification:
- Confused why the returned value is an integer but your answer is an array?
- Note that the input array is passed in by reference, which means modification to the input array will be known to the caller as well.
- Internally you can think of this:
- // nums is passed in by reference. (i.e., without making a copy)
- int len = removeElement(nums, val);
- // any modification to nums in your function would be known by the caller.
- // using the length returned by your function, it prints the first len elements.
- for (int i = 0; i < len; i++) {
- print(nums[i]);
- }
复制代码
- class Solution {
- public int removeElement(int[] nums, int val) {
-
- int len = nums.length;
-
- for(int i = 0; i< len ; i++){
-
- if(nums[i] == val){
-
- int j = i;
-
- while(j < len-1 && nums[j] == val){
-
- j++;
- }
-
- int temp = nums[i];
-
- nums[i] = nums[j];
-
- nums[j] = temp;
- }
-
-
- }
-
- int count = 0;
-
- for(int i = 0 ; i < len; i++){
-
- if(nums[i] != val){
-
- count++;
- }
- }
-
- return count;
-
- }
- }
复制代码 |
|