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[学习笔记] leetcode 108. Convert Sorted Array to Binary Search Tree

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发表于 2019-9-16 13:17:57 | 显示全部楼层 |阅读模式

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Given an array where elements are sorted in ascending order, convert it to a height balanced BST.

For this problem, a height-balanced binary tree is defined as a binary tree in which the depth of the two subtrees of every node never differ by more than 1.

Example:

Given the sorted array: [-10,-3,0,5,9],

One possible answer is: [0,-3,9,-10,null,5], which represents the following height balanced BST:

      0
     / \
   -3   9
   /   /
 -10  5
/**
 * Definition for a binary tree node.
 * public class TreeNode {
 *     int val;
 *     TreeNode left;
 *     TreeNode right;
 *     TreeNode(int x) { val = x; }
 * }
 */
class Solution {
    public TreeNode sortedArrayToBST(int[] nums) {
        if(nums.length == 0) return null;
        int start = 0;
        int end = nums.length - 1;
        TreeNode node = helper(nums,start,end);
        return node;
        
    }
    
    public TreeNode helper(int[] nums, int start, int end){
        if(start > end) return null;
        int mid = (start + end)/2;
        TreeNode node = new TreeNode(nums[mid]);
        node.left = helper(nums,start,mid-1);
        node.right = helper(nums,mid+1,end);
        
        return node;
    }
}

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