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[学习笔记] leetcode 108. Convert Sorted Array to Binary Search Tree

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发表于 2019-9-16 13:17:57 | 显示全部楼层 |阅读模式

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  1. Given an array where elements are sorted in ascending order, convert it to a height balanced BST.

  2. For this problem, a height-balanced binary tree is defined as a binary tree in which the depth of the two subtrees of every node never differ by more than 1.

  3. Example:

  4. Given the sorted array: [-10,-3,0,5,9],

  5. One possible answer is: [0,-3,9,-10,null,5], which represents the following height balanced BST:

  6.       0
  7.      / \
  8.    -3   9
  9.    /   /
  10. -10  5
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  1. /**
  2. * Definition for a binary tree node.
  3. * public class TreeNode {
  4. *     int val;
  5. *     TreeNode left;
  6. *     TreeNode right;
  7. *     TreeNode(int x) { val = x; }
  8. * }
  9. */
  10. class Solution {
  11.     public TreeNode sortedArrayToBST(int[] nums) {
  12.         if(nums.length == 0) return null;
  13.         int start = 0;
  14.         int end = nums.length - 1;
  15.         TreeNode node = helper(nums,start,end);
  16.         return node;
  17.         
  18.     }
  19.    
  20.     public TreeNode helper(int[] nums, int start, int end){
  21.         if(start > end) return null;
  22.         int mid = (start + end)/2;
  23.         TreeNode node = new TreeNode(nums[mid]);
  24.         node.left = helper(nums,start,mid-1);
  25.         node.right = helper(nums,mid+1,end);
  26.         
  27.         return node;
  28.     }
  29. }
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