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[学习笔记] leetcode 1208. Get Equal Substrings Within Budget

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发表于 2019-9-30 06:59:27 | 显示全部楼层 |阅读模式

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  1. You are given two strings s and t of the same length. You want to change s to t. Changing the i-th character of s to i-th character of t costs |s[i] - t[i]| that is, the absolute difference between the ASCII values of the characters.

  2. You are also given an integer maxCost.

  3. Return the maximum length of a substring of s that can be changed to be the same as the corresponding substring of twith a cost less than or equal to maxCost.

  4. If there is no substring from s that can be changed to its corresponding substring from t, return 0.



  5. Example 1:

  6. Input: s = "abcd", t = "bcdf", maxCost = 3
  7. Output: 3
  8. Explanation: "abc" of s can change to "bcd". That costs 3, so the maximum length is 3.
  9. Example 2:

  10. Input: s = "abcd", t = "cdef", maxCost = 3
  11. Output: 1
  12. Explanation: Each character in s costs 2 to change to charactor in t, so the maximum length is 1.
  13. Example 3:

  14. Input: s = "abcd", t = "acde", maxCost = 0
  15. Output: 1
  16. Explanation: You can't make any change, so the maximum length is 1.


  17. Constraints:

  18. 1 <= s.length, t.length <= 10^5
  19. 0 <= maxCost <= 10^6
  20. s and t only contain lower case English letters.
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  1. class Solution {
  2.     public int equalSubstring(String s, String t, int k) {
  3.         int i = 0, j;
  4.         int n = s.length();
  5.         for(j = 0; j<n ; j++){
  6.             k -= Math.abs(s.charAt(j) - t.charAt(j));
  7.             
  8.             if(k < 0) k+= Math.abs(s.charAt(i) - t.charAt(i++));
  9.         }
  10.         
  11.         return j - i;
  12.     }
  13. }
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