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[学习笔记] leetcode 11. Container With Most Water

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发表于 2019-9-30 12:30:58 | 显示全部楼层 |阅读模式

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本帖最后由 Seawolf 于 2019-9-30 12:32 编辑
  1. Given n non-negative integers a1, a2, ..., an , where each represents a point at coordinate (i, ai). n vertical lines are drawn such that the two endpoints of line i is at (i, ai) and (i, 0). Find two lines, which together with x-axis forms a container, such that the container contains the most water.

  2. Note: You may not slant the container and n is at least 2.

  3. 1.jpg

  4. The above vertical lines are represented by array [1,8,6,2,5,4,8,3,7]. In this case, the max area of water (blue section) the container can contain is 49.



  5. Example:

  6. Input: [1,8,6,2,5,4,8,3,7]
  7. Output: 49
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  1. class Solution {
  2.     public int maxArea(int[] height) {
  3.         if(height.length == 0 || height.length ==1) return 0;
  4.         int left = 0;
  5.         int right = height.length -1;
  6.         int max = Integer.MIN_VALUE;
  7.         while(left <= right ){
  8.             if(height[left] < height[right]){
  9.                 max = Math.max(max,(right - left) * Math.min(height[right],height[left]));
  10.                 left++;
  11.             }
  12.             else{
  13.                 max = Math.max(max,(right - left) * Math.min(height[right],height[left]));
  14.                 right--;
  15.                
  16.             }
  17.         }
  18.         
  19.         return max;
  20.     }
  21. }
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