|
马上注册,结交更多好友,享用更多功能^_^
您需要 登录 才可以下载或查看,没有账号?立即注册
x
本帖最后由 Seawolf 于 2019-9-30 12:32 编辑
- Given n non-negative integers a1, a2, ..., an , where each represents a point at coordinate (i, ai). n vertical lines are drawn such that the two endpoints of line i is at (i, ai) and (i, 0). Find two lines, which together with x-axis forms a container, such that the container contains the most water.
- Note: You may not slant the container and n is at least 2.
-
- The above vertical lines are represented by array [1,8,6,2,5,4,8,3,7]. In this case, the max area of water (blue section) the container can contain is 49.
-
- Example:
- Input: [1,8,6,2,5,4,8,3,7]
- Output: 49
复制代码
- class Solution {
- public int maxArea(int[] height) {
- if(height.length == 0 || height.length ==1) return 0;
- int left = 0;
- int right = height.length -1;
- int max = Integer.MIN_VALUE;
- while(left <= right ){
- if(height[left] < height[right]){
- max = Math.max(max,(right - left) * Math.min(height[right],height[left]));
- left++;
- }
- else{
- max = Math.max(max,(right - left) * Math.min(height[right],height[left]));
- right--;
-
- }
- }
-
- return max;
- }
- }
复制代码 |
|