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本帖最后由 Seawolf 于 2019-9-30 12:32 编辑 Given n non-negative integers a1, a2, ..., an , where each represents a point at coordinate (i, ai). n vertical lines are drawn such that the two endpoints of line i is at (i, ai) and (i, 0). Find two lines, which together with x-axis forms a container, such that the container contains the most water.
Note: You may not slant the container and n is at least 2.
The above vertical lines are represented by array [1,8,6,2,5,4,8,3,7]. In this case, the max area of water (blue section) the container can contain is 49.
Example:
Input: [1,8,6,2,5,4,8,3,7]
Output: 49
class Solution {
public int maxArea(int[] height) {
if(height.length == 0 || height.length ==1) return 0;
int left = 0;
int right = height.length -1;
int max = Integer.MIN_VALUE;
while(left <= right ){
if(height[left] < height[right]){
max = Math.max(max,(right - left) * Math.min(height[right],height[left]));
left++;
}
else{
max = Math.max(max,(right - left) * Math.min(height[right],height[left]));
right--;
}
}
return max;
}
}
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