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- Given an unsorted array of integers, find the length of longest increasing subsequence.
- Example:
- Input: [10,9,2,5,3,7,101,18]
- Output: 4
- Explanation: The longest increasing subsequence is [2,3,7,101], therefore the length is 4.
- Note:
- There may be more than one LIS combination, it is only necessary for you to return the length.
- Your algorithm should run in O(n2) complexity.
- Follow up: Could you improve it to O(n log n) time complexity?
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dp solution
- class Solution {
- public:
- int lengthOfLIS(vector<int>& nums) {
- if(nums.size() == 0) return 0;
- int dp[nums.size()] = {0};
- dp[0] = 1;
- int max_ans = 0;
- for(int i = 0; i < nums.size();i++){
- int max1 = 0;
- for(int j = 0; j < i; j++){
- if(nums[j] < nums[i]){
- max1 = max(max1, dp[j]);
- }
- }
-
- dp[i] = max1 +1;
- max_ans = max(max_ans,dp[i]);
- }
-
- return max_ans;
- }
- };
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